Quantitative Aptitude - Arithmetic Ability Questions

Q:

PQRA is a rectangle, AP = 22 cm, PQ = 8 cm. ΔABC is a triangle whose vertices lie on the sides of PQRA such that BQ = 2 cm and QC = 16 cm .Then the length of the line joining the mid points of the sides AB and BC is

A) 4√2 cm B) 5 cm
C) 6 cm D) 10 cm
 
Answer & Explanation Answer: B) 5 cm

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Filed Under: Area
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Q:

Ravi had five subjects in his final examination. The maximum marks in each subject are 100. If his percentage in four subjects is 80, and he scores 65 marks in the fifth subject, determine his overall percentage for the five subjects.

A) 0.78 B) 0.79
C) 0.77 D) 0.76
 
Answer & Explanation Answer: C) 0.77

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Filed Under: Percentage
Exam Prep: Bank Exams

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Q:

Given that the polynomial (x2+ ax+ b) leaves that same remainder when by (x –1) or (x + 1) What are the values of a and b respectively?

A) 4 and 0 B) 0 and 3
C) 3 and 0 D)  0 and any interger
 
Answer & Explanation Answer: D)  0 and any interger

Explanation:

Since x^2+ ax + b when divided by x-1 or x+1 leaves the same remainder

So on putting x=1 and x=-1 we get the same value

1+a+b = 1-a+b

2a=0

a=0

here b can take any value as it will always get cancelled out

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Filed Under: Numbers
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Q:

In the following question, four number pairs are given. The number on left side of (–) is related to the number on the right side of (–) with some Logic/Rule/Relation. Three are similar on basis of same Logic/Rule/Relation. Select the odd one out from the given alternatives.

 

A) 11 – 1331 B) 15 – 3375
C) 12 – 1728 D) 14 – 2788
 
Answer & Explanation Answer: D) 14 – 2788

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Filed Under: Odd Man Out
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Q:

Which of the following is correct?

A) (3x -­ 2y)2 = 9x2 -­ 12xy + 4y2 B) (3x -­ 2y)2 = 9x2 -­ 6xy + 4y2
C) (3x + 2y)2 = 9x2 -­ 12xy + 4y2 D) (3x + 2y)2 = 9x2 -­ 6xy + 4y2
 
Answer & Explanation Answer: A) (3x -­ 2y)2 = 9x2 -­ 12xy + 4y2

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Filed Under: Simplification
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Q:

If (tanA ­- tanB)/(1 + tanAtanB) = x, then the value of x is

A) tan(A -­ B) B) tan(A + B)
C) cot(A ­- B) D) cot(A + B)
 
Answer & Explanation Answer: A) tan(A -­ B)

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Q:

A bag contains coins of denominations Rs.1, Rs.5 and Rs.10. Assuming there are equal number of Rs.1, Rs.5 and Rs.10, what will be the total number of coins in the bag be if the total money is Rs. 368?

A) 69 B) 96
C) 56 D) 65
 
Answer & Explanation Answer: A) 69

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Q:

Find two numbers such that their mean proportion is 12 and third proportion is 768.

A) 3 and 24 B) 3 and 48
C) 6 and 48 D) 6 and 24
 
Answer & Explanation Answer: B) 3 and 48

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Filed Under: Ratios and Proportions
Exam Prep: Bank Exams

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