Quantitative Aptitude - Arithmetic Ability Questions

Q:

Find the next number in the given series

0.25, 8, 128, 1024, ?

A) 4096 B) 2526
C) 8486 D) 2620
 
Answer & Explanation Answer: A) 4096

Explanation:

Here given series follows a pattern that

0.25, 8, 128, 1024, ?

0.25 x 32 = 8

8 x 16 = 128

128 x 8 = 1024

1024 x 4 = 4096

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5 167122
Q:

what is the missing number in the sequence given below?

12  9  13.50  30.37  ?  341.71

A) 87.63 B) 91.12
C) 93.41 D) 97.94
 
Answer & Explanation Answer: B) 91.12

Explanation:

Given number series is 12  9  13.5  30.3  ?  341.7

Here the pattern followed by the series is

12 

12 x 0.75 = 9

9 x 1.5 = 13.5

13.5 x 2.25 = 30.3

30.37 x 3 = 91.12

91.12 x 3.75 = 341.71

 

Hence, the missing number in the sequence is 91.12.

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10 163467
Q:

Find out the wrong number in the given sequence of numbers.

582, 605, 588, 611, 634, 617, 600

A) 634 B) 611
C) 605 D) 600
 
Answer & Explanation Answer: A) 634

Explanation:

Alternatively 23 is added and 17 is subtracted from the terms. So, 634 is wrong.

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47 162542
Q:

For the circle shown below, find the length (in cm) of the largest cord of the circle.

 

 

A) 8 B) 12
C) 16 D) 18
 
Answer & Explanation Answer: C) 16

Explanation:
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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

3 161568
Q:

Which is the next number in the sequence:

1, 3, 6, 11, 20, 37, ??

A) 49 B) 56
C) 64 D) 70
 
Answer & Explanation Answer: D) 70

Explanation:

Here the given series is 1, 3, 6, 11, 20, 37, ??,

and the logic behind the series is

1 x 2 + 1 = 3

3 x 2 + 0 = 6

6 x 2 + (-1) = 11

11 x 2 + (-2) = 20

20 x 2 + (-3) = 37

37 x 2 + (-4) = 70

 

Hence, the next number in the given series is 70.

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6 161038
Q:

If 20% of a = b, then b% of 20 is the same as :

A) 4% of a B) 6% of a
C) 8% of a D) 10% of a
 
Answer & Explanation Answer: A) 4% of a

Explanation:

20% of a = b 

=> (20/100) * a = b 

 b% of 20 =(b/100) x 20 = [(20a/100)  / 100] x 20= 4a/100 = 4% of a.

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1394 158538
Q:

Find out the wrong number in the given sequence of numbers.

1, 2, 6, 15, 31, 56, 91

A) 31 B) 91
C) 56 D) 15
 
Answer & Explanation Answer: B) 91

Explanation:

1, 1 + 12 = 2, 2 + 22 = 6, 6 + 32 = 15, 15 + 42 = 31, 31 + 52 = 56, 56 + 62 = 92

Last number of given series must be 92 not 91.

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54 158310
Q:

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?

A) 1/2 B) 3/5
C) 9/20 D) 8/15
 
Answer & Explanation Answer: C) 9/20

Explanation:

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.

P(E) = n(E)/n(S) = 9/20.

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331 157510