Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If 2x + 3(5-2x) > 2 - 3x < 2x - x/3, then x can take which of the following values?

A) 0 B) -2
C) -4 D) 2
 
Answer & Explanation Answer: D) 2

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Q:

If cotA/(1 + cot2A) = x, then the value of x is

A) sinA B) cosecA
C) secA D) cosA
 
Answer & Explanation Answer: D) cosA

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Q:

If 2x-12x = 5, then what is the value x2 + 116x2 - 2

A) 19/4 B) 23/4
C) 27/4 D) 31/4
 
Answer & Explanation Answer: A) 19/4

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Q:

If tanA -­ tanB = X, then the value of X is

A) (tanA + tanB)/(1 -­ tanAtanB) B) (tanA + tanB)/(1 + tanAtanB)
C) (tanA -­ tanB)/(1-­ tanAtanB) D) (tanA -­ tanB)/(1 + tanAtanB)
 
Answer & Explanation Answer: D) (tanA -­ tanB)/(1 + tanAtanB)

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Q:

Two points P and Q are at the distance of x and y (where y > x) respectively from the base of a building and on a straight line. If the angles of elevation of the top of the building from points P and Q are complementary, then what is the height of the building?

A) xy B) √( y/ x)
C) √( x/ y) D) √( xy)
 
Answer & Explanation Answer: D) √( xy)

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Q:

Point P is the midpoint of segment AB. Co-ordinates of P are (5,-4) and A are (7,0). What will be the co-ordinates of point B?

A) (3, -8) B) (-3, -8)
C) (3, 8) D) (-3, 8)
 
Answer & Explanation Answer: A) (3, -8)

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Q:

If 13x2 = 172 - 92, find the value of x?

A) 16 B) 12
C) 8 D) 4
 
Answer & Explanation Answer: D) 4

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Q:

Out of the 60 students of a class, 29 took Mathematics, 32 took Biology and 8 took none of the two subjects. How many students took both Mathematics and Biology?

A) 8 B) 9
C) 7 D) 6
 
Answer & Explanation Answer: B) 9

Explanation:

Number of students who took only Mathematics n(m) = 29
Number of students who took only biology n(b) = 32
Total number of students n(t) = 60
Total number of students of both mathematics and biology n(m b) = 60 - 8 = 52
Total number of students who took both = 32 + 29 - 52 = 9

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