Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

Given: 5x -3(2x-7) > 3x - 1 < 7 + 4x; then x can take which of the following values?

A) 6 B) 9
C) -6 D) -9
 
Answer & Explanation Answer: C) -6

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Q:

What will be the value of r2+p2+s2-rp-ps-rs when r = 4, p = 2, s = 8?

A) 8 B) 18
C) 28 D) 38
 
Answer & Explanation Answer: C) 28

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Q:

What is the value of tan150°?

A) -√3 B) 1/√3
C) √3 D) -1/√3
 
Answer & Explanation Answer: D) -1/√3

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Q:

Which of the following equations has real and distinct roots?

A) 3x2 - 6x + 2 = 0 B) 3x2 - 6x + 3 = 0
C) x2 - 8x + 16 = 0 D) 4x2 - 8x + 4 = 0
 
Answer & Explanation Answer: A) 3x2 - 6x + 2 = 0

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Q:

The sum of 2xy(3x + 4y - 5z) and 5yz(2x - 3y) is

A) 6x2y - 8xy2 + 15y2z B) 6x2y + 8xy2 - 15y2z
C) 6x2y + 8xy2 - 15y2z - 20xyz D) 6x2y - 8xy2 + 15y2z + 20xyz
 
Answer & Explanation Answer: B) 6x2y + 8xy2 - 15y2z

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Q:

If 4x -7 < x - 2 and 5x +2/3 ≥ 3x + 1; then x can take which of the following values?

A) 2 B) -1
C) -2 D) 1
 
Answer & Explanation Answer: D) 1

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Q:

If cos 2π/3c = x, then the value of x is

A) -1/2 B) 1/2
C) -√3/2 D) √3/2
 
Answer & Explanation Answer: A) -1/2

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Q:

If a + b + c + d = 4, then the value of 1(1-a)(1-b)(1-c) + 1(1-b)(1-c)(1-d) + 1(1-c)(1-d)(1-a) + 1(1-d)(1-a)(1-b)

A) 0 B) 1
C) 4 D) 1+ abcd
 
Answer & Explanation Answer: A) 0

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