6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest?

A) 3.46%	B) 4.5%
C) 5%	D) 6%

Answer & Explanation Answer: A) 3.46%

Explanation:

Let the original rate be R%. Then, new rate = (2R)%.

Note: Here, original rate is for 1 year(s); the new rate is for only 4 months i.e.1/3 year(s).

$(\frac{725 * R * 1}{100}) + (\frac{362.50 * 2 R * 1}{100 * 3}) = 33.50$

=> (2175 + 725) R = 33.50 x 100 x 3

=> (2175 + 725) R = 10050

=> (2900)R = 10050

=> $R = \frac{10050}{2900} = 3.46$

Original rate = 3.46%

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Filed Under: Simple Interest
Exam Prep: GRE

37 28397

Q:

The second statement is the ____ of the first.

$1 . P \Rightarrow Q 2 . ~ Q \Rightarrow ~ P$

A) Converse	B) Inverse
C) Contrapositive	D) Contradiction

Answer & Explanation Answer: C) Contrapositive

Explanation:

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Filed Under: Probability
Exam Prep: Bank Exams

3 28386

Q:

In the following question, select the odd letter/letters from the given alternatives.

A) CHM	B) GLQ
C) KPV	D) NSX

Answer & Explanation Answer: C) KPV

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 28360

Q:

A bag contains 4 red and 3 black balls. A second bag contains 2 red and 4 black balls. One bag is selected at random. From the selected bag, one ball is drawn. Find the probability that the ball drawn is red.

A) 23/42	B) 19/42
C) 7/32	D) 16/39

Answer & Explanation Answer: B) 19/42

Explanation:

A red ball can be drawn in two mutually exclusive ways

(i) Selecting bag I and then drawing a red ball from it.

(ii) Selecting bag II and then drawing a red ball from it.

Let E1, E2 and A denote the events defined as follows:

E1 = selecting bag I,

E2 = selecting bag II

A = drawing a red ball

Since one of the two bags is selected randomly, therefore

P(E1) = 1/2 and P(E2) = 1/2

Now, $P (\frac{A}{E_{1}})$ = Probability of drawing a red ball when the first bag has been selected = 4/7

$P (\frac{A}{E_{2}})$ = Probability of drawing a red ball when the second bag has been selected = 2/6

Using the law of total probability, we have

P(red ball) = P(A) = $P (E_{1}) \times P (\frac{A}{E_{1}}) + P (E_{2}) \times P (\frac{A}{E_{2}})$

= $\frac{1}{2} \times \frac{4}{7} + \frac{1}{2} \times \frac{2}{6} = \frac{19}{42}$

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Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

64 28287

Q:

There are four hotels in a town. If 3 men check into the hotels in a day then what is the probability that each checks into a different hotel?

A) 1/2	B) 3/4
C) 4/7	D) 3/8

Answer & Explanation Answer: D) 3/8

Explanation:

Total cases of checking in the hotels = 4 x 4 x 4 = 64 ways.

Cases when 3 men are checking in different hotels = 4×3×2 = 24 ways.

Required probability =24/64 = 3/8

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Filed Under: Probability

46 28275

Q:

Consider the following statements:

1) The perimeter of a triangle is greater than the sum of its three medinas.

2) In any triangle ABC, if D is any point on BC, then AB + BC + CA > 2AD.

Which of the above statements is/are correct?

A) 1 only	B) 2 only
C) Both 1 and 2	D) Neither 1 nor 2

Answer & Explanation Answer: C) Both 1 and 2

Explanation:

Let ABC be the triangle and D. E and F are midpoints of BC, CA and AB respectively.

Recall that the sum of two sides of a triangle is greater than twice the median bisecting the third side,(Theorem to be remembered)

Hence in ΔABD, AD is a median

⇒

AB + AC > 2(AD)

Similarly, we get

BC + AC > 2CF

BC + AB > 2BE

On adding the above inequations, we get

(AB + AC) + (BC + AC) + (BC + AB )> 2AD + 2CD + 2BE

2(AB + BC + AC) > 2(AD + BE + CF)

∴

AB + BC + AC > AD + BE +CF

2.

To prove: AB + BC + CA > 2AD

Construction: AD is joined

Proof: In triangle ABD,

AB + BD > AD [because, the sum of any two sides of a triangle is always greater than the

third side]

----

1

In triangle ADC,

AC + DC > AD [because, the sum of any two

sides of a tri

angle is always greater than the

third side]

----

2

Adding 1 and 2 we get,

AB + BD + AC + DC > AD + AD

=> AB + (BD + DC) + AC > 2AD

=> AB + BC + AC > 2AD

Hence proved

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

1 28259

Q:

Select the odd figure out of the given series.

A) 2	B) 3
C) 4	D) 1

Answer & Explanation Answer: B) 3

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

2 28204

Q:

The length of the room is 5.5m and width is 3.75m. Find the cost of paving the floor by slabs at the rate of Rs.800 per sq meter

A) Rs.16500	B) Rs.15500
C) Rs.17500	D) Rs.18500

Answer & Explanation Answer: A) Rs.16500

Explanation:

l=5.5m w=3.75m
area of the floor = 5.5 x 3.75 = 20.625 sq m
cost of paving = 800 x 20.625 = Rs. 16500

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

18 28204

Quantitative Aptitude - Arithmetic Ability Questions

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