6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

David obtained 76, 65, 82, 67 and 85 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ?

A) 75	B) 68
C) 65	D) 60

Answer & Explanation Answer: A) 75

Explanation:

Average = (76 + 65 + 82 + 67 + 85 )/ 5 = 375/5 = 75.

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Filed Under: Average

24 26610

Q:

A wheel makes 1000 revolutions in covering a distance of 88 km. Find the radius of the wheel.

A) 14	B) 13
C) 12	D) 11

Answer & Explanation Answer: A) 14

Explanation:

Distance covered in one revolution = $\frac{88 \times 1000}{1000}$ = 88m.

$2 {πR}^{2} = 88 \Rightarrow 2 \times \frac{22}{7} \times R = 88 \Rightarrow R = 88 \times \frac{7}{44}$

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

23 26607

Q:

A and B enter into partnership. A supplies whole of the capital amounting to Rs. 45000 with the condition that the profits to be equally divided and that B pays A interest on half of the capital at 10% per annum, but receives Rs. 120 per month for carrying on the concern.Find their total yearly profit when B's income is one half of A's income.

Answer

Let the total profit be Rs. x

Amount paid to B as salary = (120 x 12)

= Rs.1440

Share of each = $\inline (\frac{x-1440}{2})$

Interest paid by B = $\inline \frac{22500\times 10}{100}=Rs.2250$

Total money received by A = $\inline \frac{x-1440}{2}+2250$

= Rs. $\inline (\frac{x+3060}{2})$

Total money received by B

$\inline [(\frac{x-1440}{2})+1440-2250]= (\frac{x-3060}{2})$

$\inline \Rightarrow \frac{1}{2}-(\frac{x+3060}{2})-(\frac{x-3060}{2})$

$\inline \Rightarrow x=9180$

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Subject: Partnership

60 26593

Q:

The ratio of water and alcohol in two different containers is 2:3 and 4:5. In what ratio we are required to mix the mixtures of two containers in order to get the new mixture in which the ratio of alcohol and water be 7:5?

A) 7:3	B) 5:3
C) 8:5	D) 2:7

Answer & Explanation Answer: B) 5:3

Explanation:

$W 1 : A 1 W 2 : A 2 . . . . . W N : A N$

2 : 3 4 : 5 5 : 7

$\frac{W 1}{W 1 + A 1} = \frac{2}{5} \frac{W 2}{W 2 + A 2} = \frac{4}{9} \frac{W N}{W N + A N} = \frac{5}{12}$

= 72/180

= 80/180

= 75/180

=> 5 : 3

Therefore, the ratio is 5: 3

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Filed Under: Alligation or Mixture
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

49 26581

Q:

The median of the data 1, 1/2, 1/2, 3/4, 1/4, 2, 1/2, 1/4, 3/4 is

A) 1/4	B) 1/2
C) 1/6	D) 3/4

Answer & Explanation Answer: B) 1/2

Explanation:

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0 26558

Q:

In how many ways can 5 different toys be packed in 3 identical boxes such that no box is empty, if any of the boxes may hold all of the toys ?

A) 36	B) 25
C) 24	D) 72

Answer & Explanation Answer: B) 25

Explanation:

The toys are different; The boxes are identical

If none of the boxes is to remain empty, then we can pack the toys in one of the following ways

a. 2, 2, 1

b. 3, 1, 1

Case a. Number of ways of achieving the first option 2 - 2 - 1

Two toys out of the 5 can be selected in $5 C_{2}$ ways. Another 2 out of the remaining 3 can be selected in $3 C_{2}$ ways and the last toy can be selected in $1 C_{1}$ way.

However, as the boxes are identical, the two different ways of selecting which box holds the first two toys and which one holds the second set of two toys will look the same. Hence, we need to divide the result by 2

Therefore, total number of ways of achieving the 2 - 2 - 1 option is ways $5 C_{2} * 3 C_{2}$ = 15 ways

Case b. Number of ways of achieving the second option 3 - 1 - 1

Three toys out of the 5 can be selected in $5 C_{3}$ ways. As the boxes are identical, the remaining two toys can go into the two identical looking boxes in only one way.

Therefore, total number of ways of getting the 3 - 1 - 1 option is $5 C_{3}$ = 10 = 10 ways.

Total ways in which the 5 toys can be packed in 3 identical boxes

= number of ways of achieving Case a + number of ways of achieving Case b= 15 + 10 = 25 ways.

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Filed Under: Permutations and Combinations

34 26558

Q:

A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and back. What is the total distance traveled by the man ?

A) 4.58 kms	B) 6.35 kms
C) 5.76 kms	D) 5.24 kms

Answer & Explanation Answer: C) 5.76 kms

Explanation:

Speed in still water = 6 kmph

Stream speed = 1.2 kmph

Down stream = 7.2 kmph

Up Stream = 4.8 kmph

x/7.2 + x/4.8 = 1

x = 2.88

Total Distance = 2.88 x 2 = 5.76 kms

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

37 26544

Q:

Find the area of a right-angled triangle whose base is 12 cm and hypotenuse is 13cm.

A) 30	B) 40
C) 50	D) 60

Answer & Explanation Answer: A) 30

Explanation:

Height of the triangle = $\sqrt{(13^{2} - 12^{2})} = \sqrt{25}$ = 5 cm.

Its area = $\frac{1}{2} * b a s e * h e i g h t$ = $\frac{1}{2} * 12 * 5$ = $30 c m^{2}$ .

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

49 26459

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