Quantitative Aptitude - Arithmetic Ability Questions

area of the field grazed = (22/7) * 14 * 14 = 616 sq feet

we can assume that Amar join into business after x months. So Amar money was invest into  (12 – x ) months.

76000×1257000×(12-x)=21

--> 912000 = 114000 ( 12 – x ) = 114 ( 12 – x ) = 912

--> x = 4

After 4 months amar join the business.

Clearly, we  have : x = (3y + 3z ) / 6 or 2x = y + z.

We know that 40% = 25

40% of 265 + 35% of 180 = 50% ?

25 x 265 + 35% of 180 = 50% ?

We know that (35% of 180 = 180% of 35) & 180% = 95

25 x 265 + 95 x 35 = 50% ?

106 + 63 = 50% ?

?= 2 x 169 = 338.

There are 7 letters in the word ‘Bengali of these 3 are vowels and 4 consonants.

Considering vowels a, e, i as one letter, we can arrange 4+1 letters in 5! ways in each of which vowels are together. These 3 vowels can be arranged among themselves in 3! ways.

Total number of words = 5! x 3!= 120 x 6 = 720

The maximum number of bows will be 4 yards (= 4 x 36 inches) divided by 15 inches.

This gives 9.6. But as a fraction of a bow is no use, we can only make 9 bows.

Let the pipe B be closed after 'K' minutes.

30/16 - K/24 = 1 => K/24 = 30/16 - 1 = 14/16

=> K = 14/16 x 24 = 21 min.

If we want to pack the drinks in the least number of cans possible, then each can should contain the maximum numbers of liters possible.As each can contains the same number liters of a drink, the number of liters in each can is a comman factor for 80,144 and 368; and it is also the highest such factor, as we need to store the maximum number of liters in each can.

So, the number of liters in each can  = HCF of 80,144 and 368 = 16 liters.

Now, number of cans of Maaza = 80/16 = 5

Number of cans of Pepsi = 144/16 = 9

Number of cans of Sprite = 368/16 = 23

Thus, the total number of cans required = 5 + 9 + 23 = 37