6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, pipe A is turned off. What is the total time required to fill the tank?

A) 10 min. 20 sec.	B) 11 min. 45 sec.
C) 12 min. 30 sec.	D) 14 min. 40 sec.

Answer & Explanation Answer: D) 14 min. 40 sec.

Explanation:

Part filled in 4 minutes =4(1/15+1/20) = 7/15

Remaining part =(1-7/15) = 8/15

Part filled by B in 1 minute =1/20 : 8/15 :: 1:x

x = (8/15*1*20) = $10 \frac{2}{3} m i n = 10 m i n 40 s e c$

The tank will be full in (4 min. + 10 min. + 40 sec.) = 14 min. 40 sec

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194 80211

Q:

Find the missing number in the given number series?

514, 470, ?, 415, 404

A) 441	B) 437
C) 426	D) 420

Answer & Explanation Answer: B) 437

Explanation:

Given number series is 514 470 ? 415 404

Here the pattern it follows is

514

514 - 44 = 470

470 - 33 = 437

437 - 22 = 415

415 - 11 = 404

Hence, the missing number in the given number series is 437.

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Filed Under: Odd Man Out
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4 80209

Q:

Solve the following :

(-4){19 - (-2) x (-8)} = ?

A) 12	B) -140
C) 140	D) -12

Answer & Explanation Answer: D) -12

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

0 79985

Q:

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

A) 1	B) 2
C) 3	D) 4

Answer & Explanation Answer: C) 3

Explanation:

Area of the park = (60 x 40) = 2400 $m^{2}$

Area of the lawn = 2109 $m^{2}$

Area of the crossroads = (2400 - 2109) = 291 $m^{2}$

Let the width of the road be x metres. Then,

$60 x + 40 x - X^{2} = 291$

$x^{2} - 100 x + 291 = 0$

(x - 97)(x - 3) = 0
x = 3.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

86 79675

Q:

Consider the following for real numbers α, β, γ and δ ?

1) sec α = 1/4

2) tan β = 20

3) cosec γ = 1/2

4) cos δ = 2

How many of the above statements are not possible?

A) one	B) two
C) three	D) four

Answer & Explanation Answer: C) three

Explanation:

Sec of any number can never be less than 1

tan can take any value from -∞ to + ∞

cosec of any number can never be less than 1

cos of any number can never be greater than 1

so option 1,3,4 are not possible

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Filed Under: Simplification
Exam Prep: Bank Exams

1 79557

Q:

Solve the following : 80÷[48−56−(60−36÷12×4)]=?

A) 5	B) 8
C) 4	D) 2

Answer & Explanation Answer: D) 2

Explanation:

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2 79273

Q:

If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle.

A) 110	B) 120
C) 130	D) 140

Answer & Explanation Answer: B) 120

Explanation:

let length = x and breadth = y then

2(x+y) = 46 => x+y = 23

x²+y² = 17² = 289

now (x+y)² = 23²

=> x²+y²+2xy= 529

=> 289+ 2xy = 529

=> xy = 120

area = xy = 120 sq.cm

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Filed Under: Area
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Job Role: Bank PO

287 79226

Q:

Find the odd man out in the following number series?

71, 88, 113, 150, 203, 277

A) 277	B) 203
C) 150	D) 113

Answer & Explanation Answer: A) 277

Explanation:

The given number series is

71 88 113 150 203 277

+17 +25 +37 +53 +74

+8 +12 +16 +21

+4 +4 +5

The series should be 71 88 112 150 203 276 i.e, the differences of the difference should be +4.

Hence, the odd man in the given series is 277.

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Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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