6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A man sells Rs.5000, 12 % stock at 156 and uinvests the proceeds parity in 8 % stock at 90 and 9 % stock at 108. He hereby increases his income by Rs. 70. How much of the proceeds were invested in each stock?

A) 4000	B) 4200
C) 4002	D) 4020

Answer & Explanation Answer: B) 4200

Explanation:

S.P of Rs. 5000 stock = $R s . (\frac{156}{100} * 5000)$ = Rs. 7800.

Income from this stock = $R s . (\frac{12}{100} * 5000)$ = Rs. 600.

Let investment in 8 % stock be x and that in 9 % stock = (7800 - x).

Therefore,

$(x * \frac{8}{90}) + (7800 - x) * \frac{9}{108} = [600 + 70]$

$\frac{4 x}{45} + \frac{7800 - x}{12} = 670 \Leftrightarrow x = 3600$

Therefore, Money invested in 8 % stock at 90 = Rs. 3600.

Money invested in 9 % at 108 = Rs. (7800-3600) = Rs. 4200.

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Filed Under: Stocks and Shares

14 9389

Q:

The probability that a card drawn from a pack of 52 cards will be a diamond or a king, is

A) 5/12	B) 4/13
C) 5/13	D) 3/14

Answer & Explanation Answer: B) 4/13

Explanation:

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Filed Under: Probability

8 9377

Q:

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

A) 648	B) 1800
C) 2700	D) 10800

Answer & Explanation Answer: B) 1800

Explanation:

Let the required number of bottles be x.

More machines, More bottles (Direct Proportion)

More minutes, More bottles (Direct Proportion)

$\begin{array}{r} \begin{matrix} m a c h i n e s & 6 : 10 \end{matrix} \\ \begin{matrix} t i m e (i n m i n) & 1 : 4 \end{matrix} \end{array}\} ⋮ ⋮ 270 : x$

=> 6 * 1 * x = 10 * 4 * 270

=> x= 1800

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Filed Under: Chain Rule

3 9375

Q:

A mixture contains alcohol and water in the ratio 4:3. If 5 liters of water is added to the mixture, the ratio becomes 4:5. Find the quantity of alcohol in the given mixture.

A) 8 Liters	B) 10 Liters
C) 18 Liters	D) 22 Liters

Answer & Explanation Answer: B) 10 Liters

Explanation:

Let the quantity of alcohol and water be 4x liters and 3x liters respectively. Then,

(4x)/(3x+5) = 4/5

=> 20x = 4(3x+5)

=> x = 2.5

Quantity of alcohol = (4 * 2.5) liters = 10 liters.

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Filed Under: Ratios and Proportions

12 9369

Q:

The number 0.127 is how much greater than 1/8 ?

A) 1/100	B) 1/1500
C) 1/2	D) 1/500

Answer & Explanation Answer: D) 1/500

Explanation:

0.127 expressed as a fraction = 127/1000

1/8 can also be expressed as (1 x 125) / (8 x 125) = 125/1000

The difference is 2/1000, which is 1/500

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Filed Under: Decimal Fractions
Exam Prep: GRE

8 9339

Q:

Each edge of a cube is increased by 20% then the percentage increase in surface area of the cube is :

A) 144%	B) 40%
C) 44%	D) 72.8%

Answer & Explanation Answer: C) 44%

Explanation:

The surface area of a cube = 6 $a^{2}$ = 6 $s i d e^{2}$

New Surface area = 6 x 1.44 $a^{2}$

Therefore, $\frac{0.44 a^{2}}{a^{2}} x 100 = 44$ %

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

13 9331

Q:

A bill for Rs. 6000 is drawn on July 14 at 5 months. It is discounted on 5th October at 10%. Find the banker's discount, true discount, banker's gain and the money that the holder of the bill receives.

A) 4390	B) 6580
C) 5880	D) 5350

Answer & Explanation Answer: C) 5880

Explanation:

Face value of the bill = Rs. 6000.

Date on which the bill was drawn = July 14 at 5 months. Nominally due date = December 14.

Legally due date = December 17.

Date on which the bill was discounted = October 5.

Unexpired time : Oct. Nov. Dec.

26 + 30 + 17 = 73 days =1/ 5Years

B.D. = S.I. on Rs. 6000 for 1/5 year

= Rs. (6000 x 10 x1/5 x1/100)= Rs. 120.

T.D. = Rs.[(6000 x 10 x1/5)/(100+(10*1/5))]

=Rs.(12000/102)=Rs. 117.64.

B.G. = (B.D.) - (T.D.) = Rs. (120 - 117.64) = Rs. 2.36.

Money received by the holder of the bill = Rs. (6000 - 120) = Rs. 5880.

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Filed Under: Banker's Discount

5 9296

Q:

Find the total number of distinct vehicle numbers that can be formed using two letters followed by two numbers. Letters need to be distinct

A) 65000	B) 64000
C) 72000	D) 36000

Answer & Explanation Answer: A) 65000

Explanation:

Out of 26 alphabets two distinct letters can be chosen in $26 P_{2}$ ways. Coming to numbers part, there are 10 ways.(any number from 0 to 9 can be chosen) to choose the first digit and similarly another 10ways to choose the second digit. Hence there are totally 10X10 = 100 ways.

Combined with letters there are $6 P_{2}$ X 100 ways = 65000 ways to choose vehicle numbers.

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Filed Under: Permutations and Combinations

3 9295

Quantitative Aptitude - Arithmetic Ability Questions

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