6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A rectangular box measures internally 1.6m long, 1m broad and 60cm deep. The number of cubical box each of edge 20cm that can be packed inside the box is:

A) 30	B) 60
C) 90	D) 120

Answer & Explanation Answer: D) 120

Explanation:

Number of blocks = $(\frac{160 \times 100 \times 60}{20 \times 20 \times 20})$ =120

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams
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10 9291

Q:

A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1cm when a man gets on it. The mass of the man is:

A) 12 kg	B) 60 kg
C) 72 kg	D) 96 kg

Answer & Explanation Answer: B) 60 kg

Explanation:

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Filed Under: Volume and Surface Area

11 9274

Q:

Half the people on a bus get off at each stop after the first, and no one gets on after the first stop. If only one person gets off at stop number 7, how many people got on at the first stop?

A) 128	B) 64
C) 32	D) 16

Answer & Explanation Answer: B) 64

Explanation:

7th stop only one was left and in each preceding stop twice the nos... there were so 6 stops before 7th.

so $2^{6} = 64$

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Filed Under: Problems on Numbers
Exam Prep: GRE

6 9263

Q:

A bus covers its journey at the speed of 80km/hr in 10hours. If the same distance is to be covered in 4 hours, by how much the speed of bus will have to increase ?

A) 85 km/hr	B) 95 km/hr
C) 105 km/hr	D) 120 km/hr

Answer & Explanation Answer: D) 120 km/hr

Explanation:

Initial speed = 80km/hr
Total distance = 80 x 10 = 800km
New speed = 800/4 =200km/hr
Increase in speed = 200 - 80 = 120km/hr

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

12 9257

Q:

The least number of four digits which is divisible by 4, 6, 8 and 10 is ?

A) 1107	B) 1080
C) 1100	D) 1208

Answer & Explanation Answer: B) 1080

Explanation:

LCM of 4, 6, 8 and 10 = 120
120) 1000 (8
960
------
40

The least number of four digits which is divisible by 4, 6, 8 and 10 => 1000 + 120 - 40 = 1080.

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Filed Under: Problems on Numbers
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8 9256

Q:

A man is riding a bike with front and back wheel circumference of 40 inches and 70 inches respectively. If the man rides the bike on a straight road without slippage, how many inches will the man have travelled when the front wheel has made 15 revolutions more than the back wheel?

A) 1100	B) 1300
C) 1400	D) 1200

Answer & Explanation Answer: C) 1400

Explanation:

Given the ratio of the circumference of front wheel is 40 inches and back wheel is 70 inches.

Distance covered = Circumference of the wheel × No. of Revolutions made by the wheel

If n is the number of revolutions made by back wheel, the number of revolutions made by front wheel is n+15

Distance covered by both the wheels is the same

i.e, 40*(n+15)=70n

n=20

Front wheel : Back Wheel

Circumference 40 : 70

Revolutions 35 : 20

Distance covered : 40×35 = 70×20 = 1400 inches.

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Filed Under: Time and Distance
Exam Prep: CAT
Job Role: Bank PO

17 9256

Q:

Raghu can complete a work in 12days working 9 hours a day. Arun can complete the same work in 8 days working 11 hours a day. If both Raghu and Arun work together, working 12 hours a day, in how many days can they complete the work ?

A) $3 \frac{4}{49} d a y s$

B) $12 \frac{4}{49} d a y s$

C) $4 \frac{3}{49} d a y s$

D) $4 \frac{12}{49} d a y s$

A) Option A	B) Option B
C) Option C	D) Option D

Answer & Explanation Answer: C) Option C

Explanation:

Raghu can complete the work in (12 x 9)hrs = 108 hrs.

Arun can complete the work in (8 x 11)hrs = 88 hrs.

Raghu's 1 hrs work = 1/108 and Arun's 1 hrs work = 1/88

(Raghu + Arun)'s 1 hrs work = $(\frac{1}{108} + \frac{1}{88}) = \frac{49}{2376}$

So, both Raghu and Arun will finish the work in $\frac{2376}{49} h r s$

Number of days of 12 hours each= $(\frac{2376}{49} \times \frac{1}{12})$ = $\frac{198}{49} = 4 \frac{3}{49} d a y s$

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Filed Under: Time and Work
Exam Prep: GATE , CAT , Bank Exams
Job Role: Bank PO , Bank Clerk

6 9252

Q:

From a tank of petrol, which contains 200 litres of petrol, the seller replaces each time with kerosene when he sells 40 litres of petrol(or its mixture). Everytime he sells out only 40 litres of petrol(pure or impure). After replacing the petrol with kerosen 4th time, the total amount of kerosene in the mixture is

A) 81.92L	B) 96L
C) 118.08L	D) None of these

Answer & Explanation Answer: C) 118.08L

Explanation:

The amount of petrol left after 4 operations

= $200 \times {(1 - \frac{40}{200})}^{4}$

= $200 \times {(\frac{4}{5})}^{4}$

= $200 \times (\frac{256}{625})$

= 81.92 litres

Hence the amount of kerosene = 200 - 81.92 = 118. 08 litres

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Filed Under: Alligation or Mixture
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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9 9248

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