Quantitative Aptitude - Arithmetic Ability Questions

since it is a combination = 38C17 = 2878 x 10^10

Let amount be Rs. x. 

Then,  [X * R * T] / [100+(R * T)]  

⇒x×12×34100+12×34 = 540 

x=  Rs.6540  

Amount = Rs. 6540.  

P.W. = Rs. (6540 – 540) =Rs. 6000.

let the diagonals of the squares be 2x and 5x respectively

ratio of their areas = 12*2x2 :12*5x2= 4:25

   0.125125...... = 0.125¯ =   125/999

Here it is asked that 3 is what percent of 5

Let 3 is K percent of 5.

=> K x 5/100 = 3

=> K = 300/5 = 60

Hence, 3 is 60% of 5.

Let the three numbers be x, y, z.

From the gien data,

x = 2y ....(1)

x = z/2 => z = 2(2y) = 4y .....(From 1)  ...........(2)

Given average of three numbers = 56

Then,

$$\begin{gathered} x + y + z3 = 56 \\ 2y + y + 4y3 = 56 (From 1 & 2) \\ 7y = 56 x 3 \\ y = 24 \end{gathered}$$

Now,

x = 2y => x = 2 x 24 = 48

z = 4y = 4 x 24 = 96

Now, the highest number is z = 96 & smallest number is y = 24

Hence, required sum of highest number and smallest number

= z + y

= 96 + 24

= 120.