6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

What is the SI on Rs.7500/- at the rate of 10% per annum for 5 years?

A) 3750	B) 2750
C) 1750	D) 750

Answer & Explanation Answer: A) 3750

Explanation:

S.I=PNR/100

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Filed Under: Simple Interest
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4 5556

Q:

'X' sells fruits at 21% profit. If X bought it for 9% less and sold it for Rs.29 less, he would have gained 25%. The cost price of fruits is?

A) Rs. 400	B) Rs. 420
C) Rs. 460	D) Rs. 480

Answer & Explanation Answer: A) Rs. 400

Explanation:

Let the cost price of the fruits be 'C.P'

From the given data, after analysis it can be solved as

(121% of C.P) - (125% of 91% of C.P) = 29

$\frac{121}{100} C . P - \frac{125}{100} x \frac{91}{100} x C . P = 29 (\frac{121}{100} - \frac{125 x 91}{100 x 100}) C . P = 29 (12100 - 125 x 91) C . P = 290000 (12100 - 11375) C . P = 290000 725 C . P = 290000 C . P = 400$

Hence, the cost price of the fruits = Rs. 400.

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Filed Under: Profit and Loss
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13 5554

Q:

Find the compound interest on Rs. 6,500 for 4 years if the rate of interest is 10% p.a. for the first 2 years and 20% per annum for the next 2 years?

A) Rs. 3845	B) Rs. 4826
C) Rs. 5142	D) Rs. 4415

Answer & Explanation Answer: B) Rs. 4826

Explanation:

We know the formula for calculating

The compound interest $C = P [{(1 + \frac{r}{100})}^{n} - 1]$ where P = amount, r = rate of interest, n = time

Here P = 5000, r1 = 10, r2 = 20

Then $C = 6500 [{(1 + \frac{10}{100})}^{2} x {(1 + \frac{20}{100})}^{2} - 1] = 6500 x \frac{1856}{2500} = \frac{65 x 1856}{25}$

C = Rs. 4826.

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Filed Under: Compound Interest
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20 5552

Q:

What is the difference between the compound interests on Rs. 5000 for $1 \frac{1}{2}$ years at 4% per annum compounded yearly and half-yearly?

A) Rs.3.06	B) Rs.2.04
C) Rs.3.65	D) Rs.5.40

Answer & Explanation Answer: B) Rs.2.04

Explanation:

C.I. when interest compounded yearly

$R s . [5000 * (1 + \frac{4}{100}) * (1 + \frac{\frac{1}{2} * 4}{100})]$

$R s . [5000 * \frac{26}{25} * \frac{51}{50}]$

=Rs.5034

C.I. when interest iscompounded half-yearly

$R s . [5000 * {(1 + \frac{2}{100})}^{3}]$

= Rs. 5306.04

Difference = Rs. (5306.04 - 5304) = Rs. 2.04

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Filed Under: Compound Interest
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1 5545

Q:

A simple interest earned on certain amount is triple the money when invested for 16 years.what is the interest rate offered ?

A) 13.33 %	B) 14.25 %
C) 16.98 %	D) 18.75 %

Answer & Explanation Answer: D) 18.75 %

Explanation:

Given,
S.I = 3 Principal Amount
=> 3A = A x 16 x R/100
By solving, we get
=> R = 18.75%

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Filed Under: Simple Interest
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7 5540

Q:

A card is drawn from a pack of 52 cards. The card is drawn at random. What is the probability that it is neither a spade nor a Jack?

A) 9/13	B) 4/13
C) 10/13	D) 8/13

Answer & Explanation Answer: A) 9/13

Explanation:

There are 13 spade and 3 more jack

Probability of getting spade or a jack:
=13+352=1652=413

So probability of getting neither spade nor a jack:
=1−413 = 9/13

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Filed Under: Probability

7 5540

Q:

A & B invest Rs. 1,16,000 & 1,44,000 respectively. B invests for 6 months. At the end of the year, B’s share is Rs. 9000, find the overall profit?

A) Rs. 23,500	B) Rs. 19,780
C) Rs. 21,700	D) Rs. 20,050

Answer & Explanation Answer: A) Rs. 23,500

Explanation:

Given A & B in partnership

A Invests 116000 for 12 months

=> A's share = 116000 x 12 = 13,92,000

B Invests for 6 months

=> B's share = 144000 x 6 = 8,64,000

Their Ratio = 1392 : 864 = 29 : 18

Let the Annual profit = P

Given B's share = Rs. 9000

=> 18/47 x P = 9000

=> P = 9000 x 47/18

=> P = 23,500

Hence, Overall profit = P = Rs. 23,500

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Filed Under: Partnership
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12 5538

Q:

The ratio of the speed of a boat downstream and speed of the stream is 9:1. If the speed of the current is 3 km per hr, find the distance travelled by the boat upstream in 5 hours.

A) 100 km	B) 98 km
C) 109 km	D) 105 km

Answer & Explanation Answer: D) 105 km

Explanation:

Let the speed of boat in still water is ‘x’ km/hr & that of stream is ‘y’ km/hr.
Then, ATQ
(x+y)/y = 9/1 9y = x + y
x = 8y
y = 3 km/hr
So, x = 24 km/hr
Upstream speed = 24-3 = 21 km/hr
Hence, distance travelled upstream in 5 hours = 21*5 = 105 km.

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Filed Under: Boats and Streams
Exam Prep: Bank Exams

8 5534

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