# Quantitative Aptitude - Arithmetic Ability Questions

## What is Quantitative Aptitude - Arithmetic Ability?

Quantitative Aptitude - Arithmetic Ability test helps measure one's numerical ability, problem solving and mathematical skills. Quantitative aptitude - arithmetic ability is found in almost all the entrance exams, competitive exams and placement exams. Quantitative aptitude questions includes questions ranging from pure numeric calculations to critical arithmetic reasoning. Questions on graph and table reading, percentage analysis, categorization, simple interests and compound interests, clocks, calendars, Areas and volumes, permutations and combinations, logarithms, numbers, percentages, partnerships, odd series, problems on ages, profit and loss, ratio & proportions, stocks &shares, time & distance, time & work and more .

Every aspirant giving Quantitative Aptitude Aptitude test tries to solve maximum number of problems with maximum accuracy and speed. In order to solve maximum problems in time one should be thorough with formulas, theorems, squares and cubes, tables and many short cut techniques and most important is to practice as many problems as possible to find yourself some tips and tricks in solving quantitative aptitude - arithmetic ability questions.

Wide range of Quantitative Aptitude - Arithmetic Ability questions given here are useful for all kinds of competitive exams like Common Aptitude Test(CAT), MAT, GMAT, IBPS and all bank competitive exams, CSAT, CLAT, SSC Exams, ICET, UPSC, SNAP Test, KPSC, XAT, GRE, Defence, LIC/G IC, Railway exams,TNPSC, University Grants Commission (UGC), Career Aptitude test (IT companies), Government Exams and etc.

A) 31 | B) 29 |

C) 18 | D) 19 |

Explanation:

Here the given number series follows a pattern of two alternate series.

1. 7 19 31 ...(Difference of 12)

2. 9 18 27 ...(Difference of 9)

Here the odd number is **29** instead of **27**

And the next number is 31 + 12 = **43** & 27 + 9 = **36**

A) 48 min. past 12. | B) 46 min. past 12. |

C) 45 min. past 12. | D) 47 min. past 12. |

Explanation:

Time from 8 a.m. on a day to 1 p.m. on the following day = 29 hours.

24 hours 10 min. of this clock = 24 hours of the correct clock.

$\frac{145}{6}$ hrs of this clock = 24 hours of the correct clock.

29 hours of this clock = $24*\frac{6}{145}*29$ hrs of the correct clock

= 28 hrs 48 min of the correct clock.

Therefore, the correct time is 28 hrs 48 min. after 8 a.m.

This is 48 min. past 12.

A) 54 | B) 10 |

C) 45 | D) 85 |

Explanation:

In given Series, all the numbers except **54** are multiples of 5.

A) 87.63 | B) 91.12 |

C) 93.41 | D) 97.94 |

Explanation:

Given number series is **12 9 13.5 30.3 ? 341.7**

Here the pattern followed by the series is

**12 **

**12 x 0.75 = 9**

**9 x 1.5 = 13.5**

**13.5 x 2.25 = 30.3**

**30.37 x 3 = 91.12**

**91.12 x 3.75 = 341.71**

Hence, the missing number in the sequence is **91.12.**

A) 87 | B) 78.5 |

C) 56.5 | D) 45 |

Explanation:

Here given

2, 3, 6, 15, **?** , 157.5

2 x 1.5 = 3

3 x 2 = 6

6 x 2.5 = 15

15 x 3 = 45

45 x 3.5 = 157.5

Therefore, the missing number is **45**

A) 4% of a | B) 6% of a |

C) 8% of a | D) 10% of a |

Explanation:

20% of a = b

=> (20/100) * a = b

b% of 20 =(b/100) x 20 = [(20a/100) / 100] x 20= 4a/100 = 4% of a.

A) 11 days | B) 12 days |

C) 13 days | D) 14 days |

Explanation:

One day's work of A, B and C = (1/24 + 1/30 + 1/40) = 1/10.

C leaves 4 days before completion of the work, which means only A and B work during the last 4 days.

Work done by A and B together in the last 4 days = 4 (1/24 + 1/30) = 3/10.

Remaining Work = 7/10, which was done by A,B and C in the initial number of days.

Number of days required for this initial work = 7 days.

Thus, the total numbers of days required = 4 + 7 = 11 days.

A) 131 | B) 94 |

C) 83 | D) 67 |

Explanation:

Here the given series **7, 11, 19, 35, ?**

follows a pattern that **(x 2 - 3) i.e,**

**7**

**7 x 2 - 3 = 11**

**11 x 2 - 3 = 19**

**19 x 2 - 3 = 35**

**35 x 2 - 3 = 67**

**67 x 2 - 3 = 131**

**Hence the next number in the given number series** is** 67.**