# Quantitative Aptitude - Arithmetic Ability Questions

## What is Quantitative Aptitude - Arithmetic Ability?

Quantitative Aptitude - Arithmetic Ability test helps measure one's numerical ability, problem solving and mathematical skills. Quantitative aptitude - arithmetic ability is found in almost all the entrance exams, competitive exams and placement exams. Quantitative aptitude questions includes questions ranging from pure numeric calculations to critical arithmetic reasoning. Questions on graph and table reading, percentage analysis, categorization, simple interests and compound interests, clocks, calendars, Areas and volumes, permutations and combinations, logarithms, numbers, percentages, partnerships, odd series, problems on ages, profit and loss, ratio & proportions, stocks &shares, time & distance, time & work and more .

Every aspirant giving Quantitative Aptitude Aptitude test tries to solve maximum number of problems with maximum accuracy and speed. In order to solve maximum problems in time one should be thorough with formulas, theorems, squares and cubes, tables and many short cut techniques and most important is to practice as many problems as possible to find yourself some tips and tricks in solving quantitative aptitude - arithmetic ability questions.

Wide range of Quantitative Aptitude - Arithmetic Ability questions given here are useful for all kinds of competitive exams like Common Aptitude Test(CAT), MAT, GMAT, IBPS and all bank competitive exams, CSAT, CLAT, SSC Exams, ICET, UPSC, SNAP Test, KPSC, XAT, GRE, Defence, LIC/G IC, Railway exams,TNPSC, University Grants Commission (UGC), Career Aptitude test (IT companies), Government Exams and etc.

A) 98 | B) 102 |

C) 87 | D) 79 |

Explanation:

The given number series is

**3, 5, 8, 15, 28, 51, ?**

Here the pattern it follows is

**3**

**3 + 2 = 5 **( add prime number less than 3 i.e, 2)

**5 + 3 = 8 **(3 is prime number less than 5)

**8 + 7 = 15 **(7 is prime number less than 8)

**15 + 13 = 28 **(13 is prime number less than 15)

**28 + 23 = 51 **(23 is prime number less than 28)

**51 + 47 = 98 **(47 is prime number less than 51)

Hence, the next number in the given number series is **98.**

A) a | B) b |

C) c | D) d |

Explanation:

We know that d=√2s

Given diagonal = 20 cm

=> s = 20/$\sqrt{2}$ cm

Therefore, perimeter of the square is 4s = 4 x 20/$\sqrt{2}$ = 40$\sqrt{2}$ cm.

A) 14 | B) 64 |

C) 29 | D) 136 |

Explanation:

The Given number series **3, 6.5, 14, 29, 64, 136** follows a pattern that

3

3 x 2 + 0.5 = 6.5

6.5 x 2 + 1 = 14

14 x 2 + 2 = 30 $\ne $29

30 x 2 + 4 = 64

64 x 2 + 8 = 136

Thus the wrong number in the series is **29**

A) 91 | B) 35 |

C) 47 | D) 69 |

Explanation:

**The next number in the series is**

**143 143 136 110**

** 0 7 26 (**Differences**)**

** ${\mathbf{1}}^{\mathbf{3}}\mathbf{}\mathbf{-}\mathbf{}\mathbf{1}\mathbf{}\mathbf{,}\mathbf{}{\mathbf{2}}^{\mathbf{3}}\mathbf{}\mathbf{-}\mathbf{}\mathbf{1}\mathbf{,}\mathbf{}{\mathbf{3}}^{\mathbf{3}}\mathbf{}\mathbf{-}\mathbf{}\mathbf{1}\mathbf{,}\mathbf{}{\mathbf{4}}^{\mathbf{3}}\mathbf{}\mathbf{-}\mathbf{}\mathbf{1}\mathbf{,}\mathbf{.}\mathbf{.}\mathbf{.}\phantom{\rule{0ex}{0ex}}\mathrm{Now}\mathrm{the}\mathrm{next}\mathrm{number}\mathrm{is}\mathrm{given}\mathrm{by}\phantom{\rule{0ex}{0ex}}\mathbf{110}\mathbf{}\mathbf{-}\mathbf{}\mathbf{(}{\mathbf{4}}^{\mathbf{3}}\mathbf{}\mathbf{-}\mathbf{}\mathbf{1}\mathbf{)}\mathbf{}\mathbf{=}\mathbf{}\mathbf{110}\mathbf{}\mathbf{-}\mathbf{}\mathbf{63}\mathbf{}\mathbf{=}\mathbf{}\mathbf{47}\mathbf{.}$**

A) 18 litres | B) 24 litres |

C) 32 litres | D) 42 litres |

Explanation:

Let the quantity of the wine in the cask originally be x litres

Then, quantity of wine left in cask after 4 operations =$\left[x{\left(1-\frac{8}{x}\right)}^{4}\right]$litres

$\therefore \left[\frac{x{\left(1-{\displaystyle \frac{8}{x}}\right)}^{4}}{x}\right]=\frac{16}{81}$

$\Rightarrow {\left[1-\frac{8}{x}\right]}^{4}={\left(\frac{2}{3}\right)}^{4}$

$\Rightarrow x=24$

A) 14 | B) 19 |

C) 33 | D) 38 |

Explanation:

Let the son's present age be x years .Then, (38 - x) = x => x= 19.

Son's age 5 years back = (19 - 5) = 14 years

A) 76 | B) 79 |

C) 85 | D) 87 |

Explanation:

Average = total runs / no.of innings = 32

So, total = Average x no.of innings = 32 x 10 = 320.

Now increase in avg = 4runs. So, new avg = 32+4 = 36runs

Total runs = new avg x new no. of innings = 36 x 11 = 396

Runs made in the 11th inning = 396 - 320 = 76

A) 28 | B) 21 |

C) 24 | D) 30 |