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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

A library has an average of 510 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is : 

A) 285 B) 290
C) 297 D) 305
 
Answer & Explanation Answer: A) 285

Explanation:

 Since the month begins with a Sunday, so there will be five Sundays in the month,

Required average = (510 * 5 + 240 * 25) / 30 = 8550/30 = 285.

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Q:

Find the odd man out from the given series?

8, 18, 56, 232, 1165 

A) 18 B) 56
C) 232 D) 1165
 
Answer & Explanation Answer: B) 56

Explanation:

The given number series 8, 18, 56, 232, 1165 

8

8 x 2 + 2 = 18

18 x 3 + 3 = 57 (not 56)

57 x 4 + 4 = 232

232 x 5 + 5 = 1165

 

Hence, the odd man in the given series is 56.

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Q:

Angles of the triangle are in the ratio of 1:2:3. Choose the correct triangle for the given ratio.

 

A) Equilateral B) Isosceles
C) Right angle D) Obtuse angled
 
Answer & Explanation Answer: C) Right angle

Explanation:
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Filed Under: Area
Exam Prep: Bank Exams

1 61391
Q:

Simplify : 528 ÷ 2835 ÷ 20112

 

A) 4/5 B) 5/4
C) 4/7 D) 7/4
 
Answer & Explanation Answer: B) 5/4

Explanation:
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Filed Under: Simplification
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1 61231
Q:

The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is :

A) 35 B) 36.5
C) 40 D) 42
 
Answer & Explanation Answer: B) 36.5

Explanation:

Correct Sum = (36 * 50 + 48 - 23) = 1825.

Correct mean = = 1825/50 = 36.5

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183 61049
Q:

Select the option that can replace the question mark (?) in the following equation.

 

0.23 - 0.130.2 + 0.12

 

A) 1/18 B) 3/40
C) -7/90 D) 7/90
 
Answer & Explanation Answer: D) 7/90

Explanation:
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Q:

Solve the following

 

24 / (20 - 12 / 3 x 8) = ?

A) -2 B) -3
C) 6 D) 3
 
Answer & Explanation Answer: A) -2

Explanation:
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Q:

If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?

A) Sunday B) Saturday
C) Tuesday D) Wednesday
 
Answer & Explanation Answer: A) Sunday

Explanation:

The year 2004 is a leap year. So, it has 2 odd days.

But, Feb 2004 not included because we are calculating from March 2004 to March 2005.

So it has 1 odd day only.

The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.

Given that, 6th March, 2005 is Monday.

6th March, 2004 is Sunday (1 day before to 6th March, 2005).

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Filed Under: Calendar

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