Quantitative Aptitude - Arithmetic Ability Questions

Q:

Find the odd figure?

 

 

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: B) 2

Explanation:
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Filed Under: Odd Man Out
Exam Prep: Bank Exams

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Q:

The perimeter of a square is 22 cm. Find its area (in cm2).

 

A) 60.5 B) 22.5  
C) 45   D) 30.25
 
Answer & Explanation Answer: D) 30.25

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Filed Under: Area
Exam Prep: Bank Exams

0 31203
Q:

How many terms are in the G.P. 3, 6, 12, 24, ......., 384 ?

A) 8 B) 9
C) 10 D) 11
 
Answer & Explanation Answer: A) 8

Explanation:

Here a = 3 and r = 6/3 = 2. Let the number of terms be n.
Then, t = 384 => a * r^(n-1) = 384
=> 3 * 2^(n-1) = 384 => 2^(n-1) = 128 = 2^(7)

=> n-1 = 7 => n = 8.

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Q:

Select the letter which does NOT belong to the group.

 

 

A) 3 B) 1
C) 2 D) 4
 
Answer & Explanation Answer: B) 1

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 31169
Q:

The cost of fencing a square field @ Rs. 20 per metre is Rs.10.080.How much will it cost to lay a three meter wide pavement along the fencing inside the field @ Rs. 50 per sq m

A) 53800 B) 43800
C) 83800 D) 73800
 
Answer & Explanation Answer: D) 73800

Explanation:

perimeter = total cost / cost per m = 10080 /20 = 504m
side of the square = 504/4 = 126m
breadth of the pavement = 3m
side of inner square = 126 - 6 = 120m
area of the pavement = (126 x126) - (120 x 120) = 246 x 6 sq m
cost of pavement = 246*6*50 = Rs. 73800

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

30 31165
Q:

A boat takes 19 hours for travelling downstream from point A to point B and coming back to a point C which is at midway between A and B. If the velocity of the stream is 4 kmph and the speed of the boat in still water is 14 kmph, what is the distance between A and B ? 

A) 180 km B) 160 km
C) 140 km D) 120 km
 
Answer & Explanation Answer: A) 180 km

Explanation:

Speed in downstream = (14 + 4) km/hr = 18 km/hr;

Speed in upstream = (14 – 4) km/hr = 10 km/hr.

Let the distance between A and B be x km. Then,

x/18 + (x/2)/10 = 19 ⇔ x/18 + x/20 = 19 ⇒ x = 180 km.

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT
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91 31105
Q:

In the following question, select the odd letter/letters from the given alternatives.

 

A) EIN   B) JNS  
C) MQV   D) OSY
 
Answer & Explanation Answer: D) OSY

Explanation:
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Q:

From 5 consonants and 4 vowels, how many words can be formed using 3 consonants and 2 vowels ?

A) 7600 B) 7200
C) 6400 D) 3600
 
Answer & Explanation Answer: B) 7200

Explanation:

From 5 consonants, 3 consonants can be selected in 5C3 ways.

 

From 4 vowels, 2 vowels can be selected in 4C2 ways.

 

Now with every selection, number of ways of arranging 5 letters is 5P5ways.

 

Total number of words = 5C3*4C2*5P5

 

                                = 10x 6 x 5 x 4 x 3 x 2 x 1= 7200

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