Quantitative Aptitude - Arithmetic Ability Questions

At 3 O'clock, Minute hand is at 12 while the Hour hand is at 3. Again the minute hand has to sweep through ( 30 x 5 ) ie 150° for reaching the figure 5 to show 25 mins. 

Simultaneously the Hour hand will also rotate for 25 mins. Thus starting from the mark, 3 the hour hand will cover an angle = (25 x 30) / 60 = 12.5° 

Hence, Angle between Hour and the Minute hand = ( 60 - 12.5 ) = 47.5°

Let 4A = 6B = 1OC = k. Then, A = k/4, B = k/6,  and C =k/10 .

A : B :C = k/4 : k/6 : k/10 = 15 : 10 : 6.

Hence, C's share (4650 *  6/31) = Rs, 900.

The given number series 100, 101, 97, 105, 90

100

100 + 1^2 = 101

101 - 2^2 = 97

97 + 3^2 = 106 ( not 105)

106 - 4^2 = 90

Hence, the odd man in the given series is 105.

This sunday morning at 8:00 AM, the watch is 5 min. Slow, and the next sunday at 8:00PM it becomes 5 min 48 sec fast.  The watch gains 5+54860 min in a time of  (7×24)+12 = 180 hours. 

To show the correct time, it has to gain 5 min.

545min→180hours

5min ->

5542×180

8313hrs=72hrs+1113hrs=3days+11hrs+20min

So the correct time will be shown on wednesday at 7:20 PM

The given number series 2676, 445, ?, 21,6, 2, 1 follows a pattern that,

From right side,

1

1 x 1 + 1 = 2

2 x 2 + 2 = 6

6 x 3 + 3 = 21

21 x 4 + 4 = 88

88 x 5 + 5 = 445

445 x 6 + 6 = 2676

Hence the missing number in the given number series is 88.

This is a quadratic equation. To find n we multiply the last terms in each bracket together (2 times -5) = -10

To find ‘a’ we multiply the first terms in each bracket together (3x times 2x) = 6x2, So a = 6.

Thus a - n = 16

To find k we multiply the first term in the first bracket by the second term in the second bracket and add the result to the product of the second term in the first bracket and the first term in the second. (-15x + 4x) = -11x. So k = -11

16 - 11 = 5