Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

What is the value of 143 + 163 + 183 + ... + 303?

A) 134576 B) 120212
C) 115624 D) 111672
 
Answer & Explanation Answer: D) 111672

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Q:

If a2b+c=b2c+a=c2a+b=1 then the value of 21+a+21+b+21+c

A) 0 B) 1
C) 2 D) 3
 
Answer & Explanation Answer: C) 2

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Q:

If 11+11+11+1x = 58, then what is the value of x?

A) 2 B) 3
C) 1 D) 4
 
Answer & Explanation Answer: A) 2

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Q:

If a+1a2 = 3, then the value of  a3+1a3 is

A) 0 B) a
C) 1/a D) 1
 
Answer & Explanation Answer: A) 0

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Q:

If a(x + y) = b(x - y) = 2ab, then the value of 2(x2 + y2)

A) 2(a2 - b2) B) 2(a2 + b2)
C) 4(a2 - b2) D) 4(a2 + b2)
 
Answer & Explanation Answer: D) 4(a2 + b2)

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Q:

Out of the 60 students of a class, 29 took Mathematics, 32 took Biology and 8 took none of the two subjects. How many students took both Mathematics and Biology?

A) 8 B) 9
C) 7 D) 6
 
Answer & Explanation Answer: B) 9

Explanation:

Number of students who took only Mathematics n(m) = 29
Number of students who took only biology n(b) = 32
Total number of students n(t) = 60
Total number of students of both mathematics and biology n(m b) = 60 - 8 = 52
Total number of students who took both = 32 + 29 - 52 = 9

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Q:

2cos[(C+D)/2]sin[(C-D)/2] is equal to

A) sinC + sinD B) sinC - sinD
C) cosC - cosD D) cosC + cosD
 
Answer & Explanation Answer: B) sinC - sinD

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Q:

On dividing 111a2b2c2 by 37a2, we get ______.

A) 2c2 B) 2b2
C) 3 D) 3b2c2
 
Answer & Explanation Answer: D) 3b2c2

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