Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If 11-13xx + 11-13yy + 11-13zz = 5 then what is the value of 1x + 1y + 1z = ?

A) 1 B) 13/11
C) 13/5 D) 4
 
Answer & Explanation Answer: D) 4

Explanation:
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0 1956
Q:

Find x, if 5x-6+5x+6 = 6

A) -4 B) 0
C) 2 D) 4
 
Answer & Explanation Answer: C) 2

Explanation:
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0 1956
Q:

If sin P + cosec P = 2, then the value of sin7P + cosec7P is

A) 1 B) 2
C) 3 D) 0
 
Answer & Explanation Answer: B) 2

Explanation:
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0 1955
Q:

If x = y + 2 then x3 -  y3 -  z3 is

A) 0 B) 3xyz
C) -3xyz D) 1
 
Answer & Explanation Answer: B) 3xyz

Explanation:
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0 1953
Q:

The sum of two positive integers is 80 & difference between them is 20. Then what is difference of squares of those numbers ?

A) 1400 B) 1600
C) 1800 D) 2000
 
Answer & Explanation Answer: B) 1600

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0 1953
Q:

Solve the following equation to find x: (x  2)2  36 = 0 : xεN

A) 4 B) 8
C) -4 D) -8
 
Answer & Explanation Answer: B) 8

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0 1951
Q:

The number whose square is equal to the difference of the squares of 37 and 23 is:-

A) 45.09 B) 28.98
C) 47.09 D) 28
 
Answer & Explanation Answer: B) 28.98

Explanation:

372  232 =840 Required number =840 = 28.98

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0 1951
Q:

What is the simplified value of cosec Acot A + tan A2 ?

A) 2cos 2A B) 1 – sin2 A
C) sec2A D) secA tanA
 
Answer & Explanation Answer: B) 1 – sin2 A

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0 1950