FACTS  AND  FORMULAE  FOR  AREA  QUESTIONS

 

 

FUNDAMENTAL CONCEPTS :

I. Results on Triangles:

1. Sum of the angles of  a triangle is 180o

2. The sum of any two sides of a triangle is greater than the third side.

3. Pythagoras Theorem : In a right - angled triangle,

Hypotenuse2=Base2+Height2

4. The line joining the mid-point of a side of a triangle to the opposite vertex is called the median.

5. The point where the three medians of a triangle meet, is called Centroid. The centroid divides each of the medians in the ratio 2 : 1.

6. In an Isosceles triangle, the altitude from the vertex bisects the base.

7. The median of a triangle divides it into two triangles of the same area.

8. The area of the triangle formed by joining the mid-points of the sides of a given triangle is one-fourth of the area of the given triangle.

 

II.Results on Quadrilaterals :


1. The diagonals of a parallelogram bisect each other

2. Each diagonal of a parallelogram divides it into two triangles of the same area.

3. The diagonals of a rectangle are equal and bisect each other.

4. The diagonals of a square are equal and bisect each other at right angles

5. The diagonals of a rhombus are unequal and bisect each other at right angles

6. A parallelogram and a rectangle on the same base and between the same parallels are equal in area.

7. Of all the parallelogram of given sides, the parallelogram which is a rectangle has the greatest area.

 

IMPORTANT FORMULAE

I. 

1. Area of a rectangle = (length x Breadth)

Length =AreaBreadth  and  Breadth=AreaLength

2. Perimeter of a rectangle = 2( length + Breadth)

 

 

II. Area of square = side2=12diagonal2 

 

III. Area of 4 walls of a room = 2(Length + Breadth) x Height

 

 

IV.

1. Area of a triangle =12×base×height

2. Area of a triangle = s(s-a)(s-b)(s-c), where a, b, c are the sides of the triangle and s=12a+b+c

3. Area of an equilateral triangle =34×side2

4. Radius of incircle of an equilateral triangle of side a=a23

5. Radius of circumcircle of an equilateral triangle of side a=a3

6. Radius of incircle of a triangle of area  and semi-perimeter s=s

 

 

V.

1. Area of a parallelogram = (Base x Height)

2. Area of a rhombus = 12×Product of diagonals

3. Area of a trapezium = 12×(sum of parallel sides)×distance between them

    

 

VI.

1. Area of a cicle = πR2, where R is the radius.

2. Circumference of a circle = 2πR.

3. Length of an arc = 2πRθ360, where θ is the central angle.

4. Area of a sector = 12arc×R=πR2θ360 

 

VII.

1. Area of a semi-circle = πR22

2. Circumference of a semi - circle = πR

Q:

The altitude drawn to the base of an isosceles triangle is 8 cm and the perimeter is 32 cm. Find the area of the triangle.

A) 24 B) 48
C) 60 D) 72
 
Answer & Explanation Answer: B) 48

Explanation:

Let ABC be the isosceles triangle and AD be the altitude 

Let AB = AC = x. Then, BC = (32 - 2x). 

Since, in an isosceles triangle, the altitude bisects the base,
so BD = DC = (16 - x).
In triangle ADC,AC2=AD2+DC2 

x2=82+16-x2x=10 

BC = (32- 2x) = (32 - 20) cm = 12 cm. 

Hence, required area =  12*BC*AD=12*12*8=48cm2

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Q:

Find the ratio of the areas of the incircle and circumcircle of a square ?

A) 1 : 4 B) 4 : 1
C) 2 : 1 D) 1 : 2
 
Answer & Explanation Answer: D) 1 : 2

Explanation:

Let the side of the square be x. Then, its diagonal = 2x.  

 

Radius of incircle = x/2  and radius of circumcircle =2x2 . k11482389216.png image

Therefore, required ratio = πx24:πx22 = 14:12=1:2

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Q:

A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed?

A) 56m B) 65m
C) 34m D) 36m
 
Answer & Explanation Answer: A) 56m

Explanation:

Length of the wire fencing = perimeter = 2(90 + 50) = 280 metres

Two poles will be kept 5 metres apart. Also remember that the poles will be placed along the perimeter of the rectangular plot, not in a single straight line which is very important.

 

Hence number of poles required = 280 / 5 = 56

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Q:

A sector of 120 degrees, cut out from a circle, has an area of 66/7 sq cm. Find the radius of the circle.

A) 1cm B) 2cm
C) 3cm D) 4cm
 
Answer & Explanation Answer: C) 3cm

Explanation:

πr=667

 r =3

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Q:

A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m , then the altitude of the triangle is

A) 200m B) 300m
C) 400m D) 100m
 
Answer & Explanation Answer: A) 200m

Explanation:

Let the triangle and parallelogram have common base b, 

let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m), then  

Area of triangle    = 12×b×h1 

Area of rectangle  = b*h2 

As per Given,

12*b*h1=b*h2

12*b*h1=b*100

 h1=200

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Q:

If the diagonals of a rhombus are 24cm and 10cm the area and the perimeter of the rhombus are respectively.

A) 10 B) 11
C) 12 D) 13
 
Answer & Explanation Answer: D) 13

Explanation:

Area = 12*diagonal1*12diagonal2 = 12*24*10 sq.cm  

 

12*daigonal1=12*24=12cm 

 

12*diagonal2=12*10=5cm 


side of a rhombus = (12)² + (5)² = 169      => AB = 13cm

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Q:

If a square and a rhombus stand on the same base, then the ratio of the areas of the square and the rhombus is:

A) 1:1 B) 1:2
C) 1:3 D) 1:4
 
Answer & Explanation Answer: A) 1:1

Explanation:

A square and a rhombus on the same base are equal in area

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Q:

The area of the circle is 220 sq.m, the area of the square inscribed in a circle will be

A) 49 B) 70
C) 140 D) 150
 
Answer & Explanation Answer: C) 140

Explanation:

area of a square = 12diagonal2

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