Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If (4x - 3) - (2x + 1) = 4, then the value of x is

A) 0 B) 1
C) 2 D) 3
 
Answer & Explanation Answer: C) 2

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0 1899
Q:

On dividing 8a2b2c2 by 4a2, we get

A) 2b2 B) 2c2
C) 2b2c2 D) 2
 
Answer & Explanation Answer: C) 2b2c2

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0 1899
Q:

What will be the roots of the quadratic equation x2 - 25x + 156 = 0?

A) 12, 13 B) 25, 1
C) 9, 16 D) 31, 6
 
Answer & Explanation Answer: A) 12, 13

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0 1898
Q:

If a + b + c = 9 and ab + bc + ca = 18, then what is the value of a3 + b3 + c3  3abc?

A) 189 B) 243
C) 361 D) 486
 
Answer & Explanation Answer: B) 243

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0 1898
Q:

If cos3A = X, then value of X?

A) 4cos3A - 3cosA B) 4cos3A + 3cosA
C) 3cosA - 4cos3A D) cosA + 4cos3A
 
Answer & Explanation Answer: A) 4cos3A - 3cosA

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1 1897
Q:

What is the slope of the line, perpendicular to the line 3x - 6y = 4?

A) -2 B) 2
C) 2/3 D) -2/3
 
Answer & Explanation Answer: A) -2

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0 1897
Q:

If a + b = 5 and ab = 6, then what is the value of a3 + b3?

A) 32 B) 38
C) 35 D) 34
 
Answer & Explanation Answer: C) 35

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0 1896
Q:

θ is a positive acute angle and sinθ ­ cosθ = 0, then the value of secθ + cosecθ is

A) 2 B) √2
C) 2√2 D) 3√2
 
Answer & Explanation Answer: C) 2√2

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0 1895