255+ Data Interpretation Questions and Answers With Explanation

Q:

Study the following table and answer the questions based on it.

Below is the Household Expenditure (in Thousands Rupees) per annum.

What is the total Household Expenditure for the year 2012?

A) Rs. 89,900	B) Rs. 87,120
C) Rs. 89,100	D) Rs. 88,200

Answer & Explanation Answer: A) Rs. 89,900

Explanation:

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Filed Under: Table Charts
Exam Prep: Bank Exams

1 34048

Q:

A school has four sections A, B, C, D of Class IX students.

1. If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context?

A. Half yearly examinations were more difficult.

B. Annual examinations were more difficult.

C. Both the examinations had almost the same difficulty level.

D. The two examinations cannot be compared for difficulty level.

2. How many students are there in Class IX in the school?

A. 336 B.189 C. 335 D. 430

3. Which section has the maximum pass percentage in at least one of the two examinations?

A. A Section B. B Section C. C Section D. D Section

4. Which section has the maximum success rate in annual examination?

A. A Section B. B Section C. C Section D. D Section

5. Which section has the minimum failure rate in half yearly examination?

A. A section B. B section C. C section D. D section

Half yearly examinations were more difficult.

If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context? - See more at: https://www.theonlinetestcentre.com/table-charts7.html#sthash.slrcbjro.dpuf

Answer

1. ANSWER : C

Explanation - Number of students who passed half-yearly exams in the school

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)
= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

2. ANSWER : D

Explanation - Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class:

= (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)

= 430.

3. ANSWER : D

Explanation- Pass percentages in at least one of the two examinations for different sections are:

For Section A = $\frac{14 + 6 + 64}{28 + 14 + 6 + 64} \times 100 = \frac{84}{112} \times 100$ % = 75%

For Section B = $\frac{12 + 17 + 55}{23 + 12 + 17 + 55} \times 100$ % = 78.5%

For Section C = $\frac{8 + 9 + 46}{17 + 8 + 9 + 46} \times 100$ %= 78.75%

For Section D = $\frac{13 + 15 + 76}{27 + 13 + 15 + 76} \times 100$ %= 79.39%

Clearly ,the pass percentage is maximum for Section D

4. ANSWER : A

Explanation - Total number of students passed in annual exams in a section

= [ (No. of students failed in half-yearly but passed in annual exams) + (No. of students passed in both exams) ] in that section

Success rate in annual exams in Section A= $\frac{14 + 64}{112} \times 100$ % = 69.64%

Similarly, success rate in annual exams in:

Section B = $\frac{12 + 55}{107} \times 100$ % = 62.62%

Section C = $\frac{8 + 46}{80} \times 100$ % = 67.5%

Section D = $\frac{89}{131} \times 100$ % = 67.94%

Clearly, the success rate in annual examination is maximum for Section A.

5. ANSWER : D

Explanation - Total number of failures in half-yearly exams in a section

= [ (Number of students failed in both exams) + (Number of students failed in half-yearly but passed in Annual exams) ] in that section

Failure rate in half-yearly exams in Section A %= 37.5 %

Similarly, failure rate in half-yearly exams in:

Section B = 32.71%

Section C = 31.25%

Section D = 30.53%

Clearly, the failure rate is minimum for Section D.

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)

= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

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Subject: Table Charts Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

123 33751

Q:

Study the given bar graph and pie chart to answer the following questions.

The bar graph shows the production (in thousand tonnes) of Wheat, Rice and Maize in different states.

The pie-chart shows the percentage of agricultural land in the given six states.

Productivity = $\frac{Total\: Production}{Area\: of\: agricultural\: land}$

1.The productivity of which state is the maximum ?

1. Bihar 2. Haryana 3. Punjab 4. UP 5. MP

2.The production of which state is the maximum ?

1. Bihar 2. MP 3. Haryana 4. UP 5. Punjab

3.The prodution of wheat in punjab is what per cent more than the production of Maize in odisha ?

1. 350% 2. 250% 3. 300% 4. 200% 5. 400%

4.What is the ratio of the production of Rice in Bihar to the production of Wheat in Haryana ?

1. 2:3 2. 3:2 3. 2:1 4. 1:1 5. 1:2

5.If MP exports 40% of Rice at the rate of Rs.30 per kg and UP exports 30% of Rice at the rate of Rs.32 per kg, then what is the ratio of the income from the exports ?

1. 65:48 2. 31:42 3. 43:54 4. 57:62 5. 1:2

Answer

1. Answer : 2

Explanation : Productivity = Total production/area of Agr.land

Productivity of UP = [ (35000+30000+25000) / (30/100) ] = 300000

Productivity of MP = [ (30000+37500+27500) / (25/100) ] = 380000

Productivity of Bihar = [ (22500+27500+25000) / (20/100) ] = 375000

Productivity of Odisha = [ (22500+15000+10000) / (5/100) ]= 950000

Productivity of Haryana = [ (30000+25000+35000) / (8/100) ] = 1125000

Productivity of Punjab = [ (40000+35000+30000) / (12/100) ] = 875000

The Productivity of Haryana is the maximum.

2. Answer : 5

Explanation : Production of Punjab is maximum = 105000 tonnes

3. Answer : 3

Explanation : Production of Wheat in Punjab = 40000 tones

Production of Maize in Odisha = 10000 tones

Required % = (40000 - 10000)/100 = 300%

4. Answer : 4

Explanation : The ratio of prodution of Rice in Bihar to the production of Wheat in Haryana = 25000 tonnes : 25000 tonnes = 1 : 1

5. Answer : 1

Explanation : Income of MP from export of 40% of Rice at the rate of Rs.30 per kg = Rs.39crore

Income of UP from export of 30% of Rice at the rate of Rs.32 per kg = Rs.28.8 crore

Required ratio = 39 : 28.8 = 390 : 288 = 65 : 48

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Subject: Bar Charts Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

131 30513

Q:

Study the following table and answer the questions based on it. Expenditures of a Company (in Pesetas) per Annum Over the given Years.

1. What is the average amount of interest per year which the company had to pay during this period?

A. 32.43 B. 33.72 C. 34.18 D. 36.66

2. The total amount of bonus paid by the company during the given period is approximately what percent of the total amount of salary paid during this period?

A. 0.1% B. 0.5% C. 1.0% D. 1.25 %

3. Total expenditure on all these items in 1998 was approximately what percent of the total expenditure in 2002?

A. 62% B. 66% C. 69% D. 71%

4. The total expenditure of the company over these items during the year 2000 is?

A. 544.44 B. 501.11 C. 446.46 D. 478.87

5. The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately?

A. 4 : 7 B. 10 : 13 C. 15 : 18 D. 5 : 8

The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

The total expenditure of the company over these items during the year 2000 is? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

0.1%

What is the average amount of interest per year which the company had to pay during this period? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

Answer

1. ANSWER : D

Explanation -

Average amount of interest paid by the company during the given period

= $R s . \frac{23.4 + 32.5 + 41.6 + 36.4 + 49.4}{5} l a k h s = R s . \frac{183.3}{5} l a k h s$

= Rs. 36.66 lakhs

2. ANSWER : C

Explanation -

Required Percentage = $\frac{3.00 + 2.52 + 3.84 + 3.68 + 3.96}{288 + 342 + 324 + 336 + 420} \times 100$ %

= $\frac{17}{1710} \times 100$ % $\approx$ 1%

3. ANSWER: C

Explanation -

Required Percentage = $\frac{288 + 98 + 3.00 + 23.4 + 83}{420 + 142 + 3.96 + 49.4 + 98} \times 100$

= $\frac{495.4}{713.36} \times 100$ $\approx$ 69.45%

4. ANSWER: A

Explanation - Total expenditure of the Company during 2000 = (324 + 101 + 3.84 + 41.6 + 74) lakhs = 544.44 lakhs

5. ANSWER : B

Explanation -

Required ratio = $\frac{83 + 108 + 74 + 88 + 98}{98 + 112 + 101 + 133 + 142}$

= $\frac{451}{586}$

= $\frac{1}{1.3} = \frac{10}{13}$

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Subject: Table Charts

60 22564

Q:

Study the following graph carefully and answer the questions given below:

Distribution of candidates who were enrolled for MBA entrance exam and the candidates (out of those enrolled) who passed the exam in different institutes:

1. What percentage of candidates passed the Exam from institute T out of the total number of candidates enrolled from the same institute?

A. 50% B. 62.5% C. 75% D. 80%

2. Which institute has the highest percentage of candidates passed to the candidates enrolled?

A. Q B. R C. V D. T

3. The number of candidates passed from institutes S and P together exceeds the number of candidates enrolled from institutes T and R together by:

A. 228 B. 279 C. 399 D. 407

4. What is the percentage of candidates passed to the candidates enrolled for institutes Q and R together?

A. 68% B. 80% C. 74% D. 65%

5. What is the ratio of candidates passed to the candidates enrolled from institute P?

A. 9:11 B. 14:17 C. 6:11 D. 9:17

Answer

1. ANSWER : C

Explanation - Required percentage= $\frac{9 % o f 5700}{8 % o f 8550} \times 100$ % = $\frac{9 \times 5700}{8 \times 8550} \times 100$ % = 75%

2. ANSWER : B

Explanation - The percentage of candidates passed to candidates enrolled can be determined for each institute as under:

P = $\frac{18 % o f 5700}{22 % o f 8550} \times 100$ % = 54.55%

Q = $\frac{17 % o f 5700}{15 % o f 8550} \times 100$ % = 75.56%

R = $\frac{13 % o f 5700}{10 % o f 8550} \times 100$ % = 86.67%

S = $\frac{16 % o f 5700}{17 % o f 8550} \times 100$ % = 62.75%

T = $\frac{9 % o f 5700}{8 % o f 8550} \times 100$ % = 75%

V= $\frac{15 % o f 5700}{12 % o f 8550} \times 100$ % = 83.33%

X= $\frac{12 % o f 5700}{16 % o f 8550} \times 100$ % = 50%

Highest of these is 86.67% corresponding to institute R.

3. ANSWER : C

Explanation - Required difference = [(16% + 18%) of 5700] - [(8% + 10%) of 8550]

= [(34% of 5700) - (18% of 8550)]

= (1938 - 1539)

= 399

4. ANSWER : B

Explanation - Candidates passed from institutes Q and R together = [(13% + 17%) of 5700] = 30% of 57000.

Candidates enrolled from institutes Q and R together = [(15% + 10%) of 8550] = 25% of 8550.

Required Percentage = $\frac{30 % o f 5700}{25 % o f 8550} \times 100$ % = 80%

5. ANSWER : C

Explanation - Required ratio = $\frac{18 % o f 5700}{22 % o f 8550}$ = 6/11

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Subject: Pie Charts

52 15989

Q:

Refer the below data table and answer the following question.

What is the ratio of boys to girls ?

A) 26 : 37	B) 39 : 28
C) 28 : 39	D) 37 : 26

Answer & Explanation Answer: D) 37 : 26

Explanation:

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Exam Prep: Bank Exams

4 15547

Q:

The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year

1.What is the difference between the total number of Technicians added to the Company and the total number of Accountants added to the Company during the years 1996 to 2000?

A. 128 B. 112 C. 96 D. 88

2. What was the total number of Peons working in the Company in the year 1999?

A. 1312 B. 1192 C. 1088 D. 968

3. For which of the following categories the percentage increase in the number of employees working in the Company from 1995 to 2000 was the maximum?

A. Managers B. Technicians C. Operators D. Accountants

4. What is the pooled average of the total number of employees of all categories in the year 1997?

A. 1325 B. 1195 C. 1265 D. 1235

5. During the period between 1995 and 2000, the total number of Operators who left the Company is what percent of total number of Operators who joined the Company?

A. 19% B. 21% C. 27% D. 29%

Answer

1. ANSWER : D

Explanation - Required difference

= (272 + 240 + 236 + 256 + 288) - (200 + 224 + 248 + 272 + 260)

= 88.

2. ANSWER : B

Explanation - Total number of Peons working in the Company in 1999

= (820 + 184 + 152 + 196 + 224) - (96 + 88 + 80 + 120)

= 1192.

3. ANSWER : A

Explanation - Number of Managers working in the Company:

In 1995 = 760.
In 2000 = (760 + 280 + 179 + 148 + 160 + 193) - (120 + 92 + 88 + 72 + 96)= 1252.

Therefore, Percentage increase in the number of Managers

= $\frac{(1252 - 760)}{760} \times 100$ %= 64.74%

Number of Technicians working in the Company:
In 1995 = 1200.
In 2000 = (1200 + 272 + 240 + 236 + 256 + 288) - (120 + 128 + 96 + 100 +112) = 1936.

Therefore, Percentage increase in the number of Technicians

= $\frac{(1936 - 1200)}{1200} \times 100$ % = 61.33%

Number of Operators working in the Company:

In 1995 = 880.
In 2000 = (880 + 256 + 240 + 208 + 192 + 248) - (104 + 120 + 100 + 112 + 144) = 1444.

Therefore, Percentage increase in the number of Operators

= $\frac{(1444 - 880)}{880} \times 100$ % = 64.09%

Number of Accountants working in the Company:

In 1995 = 1160.
In 2000 = (1160 + 200 + 224 + 248 + 272 + 260) - (100 + 104 + 96 + 88 + 92) = 1884.

Therefore, Percentage increase in the number of Accountants

= $\frac{(1884 - 1160)}{1160} \times 100$ % = 62.14%

Number of Peons working in the Company:

In 1995 = 820.
In 2000 = (820 + 184 + 152 + 196 + 224 + 200) - (96 + 88 + 80 + 120 + 104) = 1288.

Therefore, Percentage increase in the number of Peons

= $\frac{(1288 - 820)}{820} \times 100$ % = 57.07%

Clearly, the percentage increase is maximum in case of Managers.

4. ANSWER : B

Explanation - Total number of employees of various categories working in the Company in 1997 are:

Managers = (760 + 280 + 179) - (120 + 92) = 1007.

Technicians = (1200 + 272 + 240) - (120 + 128) = 1464.

Operators = (880 + 256 + 240) - (104 + 120) = 1152.

Accountants = (1160 + 200 + 224) - (100 + 104) = 1380.

Peons = (820 + 184 + 152) - (96 + 88) = 972.

Therefore, Pooled average of all the five categories of employees working in the Company in 1997 = 1/5 x (1007 + 1464 + 1152 + 1380 + 972)

= 1/5 x (5975)

= 1195.

5. ANSWER : D

Explanation - Total number of Operators who left the Company during 1995 - 2000

= (104 + 120 + 100 + 112 + 144)

= 580.

Total number of Operators who joined the Company during 1995 - 2000

= (880 + 256 + 240 + 208 + 192 + 248

= 2024.

Therefore, Required Percentage

= (580/2024)x100% = 28.66% ~= 29%.

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Subject: Table Charts

33 14532

Q:

Refer the below data table and answer the following question.

If the company has issued six lakh shares between its five partners and if chinmay offers to sell 15,000 of his shares to Dhiraj, then Dhiraj will have how many shares?

A) 45000 shares	B) 30000 shares
C) 60000 shares	D) 15000 shares

Quantitative Aptitude - Data Interpretation Questions

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