# Logical Venn Diagram Questions

A) 21 | B) 22 |

C) 23 | D) 24 |

Explanation:

Let us assume the two persons who can speak two languages speak Hindi and Tamil. The third person then speaks all the three languages.

Tamil – Number of persons who can speak is 6. Only Tamil 6 – 2 – 1 = 3

Hindi - Number of persons who can speak is 15. Only Hindi 15 – 2 – 1 12

Gujarati – Number of persons who can speak is 6. Only Gujarati 6 – 1 = 5

Thus the number of persons who can speak only one language is 3 + 12 + 5 = 20

Number of persons who can speak two languages = 2

Number of person who an speak all the languages = 1

Total number of persons = 23.

A) 1 | B) 2 |

C) 3 | D) 4 |

Explanation:

Some *Students *can be *Cricket players*. Some *Cricket players *can be *Tennis fans*. Some *Students *can be *Tennis fans*. So, the given items are partly related to each other.

A) 123 | B) 231 |

C) 312 | D) 321 |

Explanation:

No. of people who read Hindu = 285

No. of people who read TOI = 127

No. of people who read IE = 212

Now,

No. of people who read Hindu and TOI both is = 20

No. of people who read TOI and IE both is = 35

No. of people who read Hindu and IE both is = 29

Let No. of people who read Hindu , TOI and IE all is = x ;

So, only Hindu is = 285-20-29-x = 236-x ;

Only TOI is = 127-20-35-x = 72-x ;

Only IE is = 212-35-29-x = 148-x ;

Now, 236-x + 72-x + 148-x + 20 + 29 + 35 + x + 50 = 500 590 -2x = 500

So, x = 45 this is the value who read all the 3 dailies.

So, No. of people who read only one paper is = 236-45 + 72-45 + 148-45 = 191 + 27 + 103 = 321.

A) a | B) b |

C) c | D) d |

Explanation:

All *Carrots* are *Vegetables*. All *Vegetables* are *Foods*.

A) 45 | B) 44 |

C) 46 | D) 24 |

Explanation:

Given U=120

5% of 120 = 6

Therefore, Students who can play Chess alone or Carroms alone = 120 - (30+40+6)= 44

A) 1 | B) 2 |

C) 3 | D) 4 |

A) 9 | B) 14 |

C) 24 | D) 21 |

Explanation:

Given that,

Members in football team = n(f) = 10

Members in science club = n(s) = 14

Members in both football team and science club = n(f ^ s) = 5

Then, Members in only football team = n(F) = 10 - 5 = 5

Members in only science team = n(S) = 14 - 5 = 9

Hence, members in only football or science team **= n(FUS) = n(F) + n(S) - n(f^s) **

**= 9 + 5 - 5**

**= 9.**

Hence, many students belong to only science club team or football team **= 9.**