A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Area of the park = (60 x 40) = 2400m2
Area of the lawn = 2109m2
Area of the crossroads = (2400 - 2109) = 291m2
Let the width of the road be x metres. Then,
(x - 97)(x - 3) = 0 x = 3.
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