1
Q:

Select the option that represents the number of parallelograms in the given figure.

 

 

A) 4 B) 2
C) 3 D) 1

Answer:   A) 4



Explanation:
Subject: Arithmetical Reasoning
Exam Prep: Bank Exams
Q:

In a note collection, there is one new Rs.2000 note for every three old Rs.500 notes. 10 more new Rs.2000 notes are added to the collection and the ratio of new Rs.2000 notes to old Rs.500 notes would be 1: 2. Based on the information, the total number of notes in the collection now becomes?

A) 60 B) 30
C) 70 D) 90
 
Answer & Explanation Answer: D) 90

Explanation:

Let 'x' be the number of new Rs.2000 notes.

Given for one new 2000 note there are three old 500 notes.

i.e, 3x


Given 10 more new Rs.2000 notes are added to the collection
and the ratio of new Rs.2000 notes to old Rs.500 notes 


x+103x=12x=20

Therefore, number of new Rs.2000 notes =  x+10 = 30.

old Rs.500 notes = 3x = 60.

Thus, the total number of notes in the collection  = 30 + 60 = 90.

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Exam Prep: CAT
Job Role: Bank PO

18 4374
Q:

In a certain office, 1/3 of workers are women, 1/2 of the women are married and 1/3 of the married women have children. If 3/4  of the men are married and 2/3  of the married men have children, what part of the workers are without children?

A) 5/18 B) 4/9
C) 11/18 D) 17/36
 
Answer & Explanation Answer: C) 11/18

Explanation:

Let the total number of workers be x. Then, 

 

Number of women = x/3 and number of men = x - x/3  = 2x/3

 

Number of women having children = x/18

 

Number of men having children = x/3

 

Number of workers having children = (x/18) + (x/3) = 7x/18

  

Therefore, workers having no children = x - 7x/18 = 11/18 of all workers.

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Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

62 22810
Q:

The following question is based on the given data for an examination.

A. Candidates appeared                 10500

B. Passed in all the five subjects     5685

C. Passed in three subjects only     1498

D. Passed in two subjects only       1250

E. Passed in one subject only           835

F. Failed in English only                       78

G. Failed in Maths only                      275

H. Failed in Physics only                    149

I. Failed in Chemistry only                147

J. Failed in Biology only                     221

 

How many candidates passed in at least four subjects ?

A) 6555 B) 5685
C) 1705 D) 870
 
Answer & Explanation Answer: A) 6555

Explanation:

Candidates passed in atleast four subjects

= (Candidates passed in 4 subjects) + (Candidates Passed in all 5 subjects)

= (Candidates failed in only 1 subject ) + ( Candidates passed in all subjects)

= (78 + 275 + 149 + 147 + 221) + 5685 = 870 + 5685 = 6555    

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53 30989
Q:

A man has a certain number of small boxes to pack into parcles. If he packs 3, 4, 5 or 6 in a parcel, he is left with one over; if he packs 7 in a parcle, none is left over. What is the number of boxes, he may have to pack?

A) 106 B) 301
C) 309 D) 400
 
Answer & Explanation Answer: B) 301

Explanation:

Clearly, the required number would be such that it leaves a remainder of 1 when divided by 3, 4, 5, or 6 and no remainder when divided by 7. Thus, the number must be of the form (L.C.M of 3, 4, 5, 6) x + 1 i.e., (60x + 1 ) and a multiple of 7. Clearly, for x = 5, the number is a multiple of 7. So the number is 301.

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42 11730
Q:

Ayush was born two years after his father's marriage. His mother is five years younger than his father but 20 years older than Ayush who is 10 years old. At what age did the father get married ?

A) 23 years B) 25 years
C) 33 years D) 35 years
 
Answer & Explanation Answer: A) 23 years

Explanation:

Ayush's present age = 10 years.

His mother's present age = (10 + 20) years = 30 years.

Ayush's father's present age = (30 + 5) years = 35 years.

Ayush's father's age at the time of Ayush's birth = (35 - 10) years = 25 years.

Therefore Ayush's father's age at the time of marriage = (25 - 2) years = 23 years.

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223 26256
Q:

In three coloured boxes - Red, Green and Blue, 108 balls are placed. There are twice as many balls in the green and red boxes combined as there are in the blue box and twice as many in the blue box as there are in the red box. How many balls are there in the green box ?

A) 18 B) 36
C) 45 D) None of these
 
Answer & Explanation Answer: D) None of these

Explanation:

Let R, G and B represent the number of balls in red, green and blue boxes respectively.

 

Then, 

 

R + G + B = 108 ...(i),

 

G + R = 2B ...(ii)

 

B = 2R ...(iii)

 

From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.

 

Putting G = 3R and B = 2R in (i), we get:

 

R + 3R + 2R = 108 =>  6R = 108 => R = 18.

 

Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.

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173 30989
Q:

Ravi's brother is 3 years senior to him. His father was 28 years of age when his sister was born while his mother was 26 years of age when he was born. If his sister was 4 years of age when his brother was born, what were the ages of Ravi's father and mother respectively when his brother was born ?

A) 32 years, 23 years B) 32 years, 29 years
C) 35 years, 29 years D) 35 years, 33 years
 
Answer & Explanation Answer: A) 32 years, 23 years

Explanation:

When Ravi's brother was born, let Ravi's father's age = x years and mother's age = y years.

Then, sister's age = (x - 28) years. So, x - 28 = 4 or x = 32.

Ravi's age = (y - 26) years. Age of Ravi's brother = (y - 26 + 3) years = (y - 23) years.

Now, when Ravi's brother was born, his age = 0 i.e. y - 23 = 0 or y = 23.

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55 14811
Q:

Today is Varun's birthday. One year, from today he will be twice as old as he was 12 years ago. How old is Varun today ?

A) 20 years B) 22 years
C) 25 years D) 27 years
 
Answer & Explanation Answer: C) 25 years

Explanation:

Let Varun's age today = x years. 

Then, Varun's age after 1 year = (x + 1) years.

Therefore x + 1 = 2 (x - 12) =>  x + 1 = 2x - 24 =>  x = 25.

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318 37258