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Q:

Consider the following frequency distribution:

x     f

8     6

5     4

6     5

10    8

9     9

4     6

7     4

What is the median for the distribution?

A) 6 B) 7
C) 8 D) 9

Answer:   C) 8



Explanation:
Summation of frequencies = 6+4+5+8+9+6+4 = 42
Median = mid value = average of 21st and 22nd value
Arranging data in increasing order we get

x     f

4     6

5     4

6     5

7     4

8     6

9     9

10    8

 
So mid value i.e 21st and 22nd value = 8
Subject: Average
Exam Prep: Bank Exams
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 The average age of 8 men is increased by years when two of them whose ages are 21 years and 23 years are replaced by two new men. The average age of the two new men is :

A) 20 B) 30
C) 40 D) 50
 
Answer & Explanation Answer: B) 30

Explanation:

Total age increased = (8 * 2) years = 16 years.

Sum of ages of two new men = (21 + 23 + 16) years = 60 years

Average age of two new men = (60/2) years = 30 years.

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Q:

The average age of a group of persons going for picnic is 16 years. Twenty new persons with an average age of 15 years join the group on the spot due to which their average age becomes 15.5 years. The number of persons initially going for picnic is :

A) 15 B) 20
C) 23 D) 24
 
Answer & Explanation Answer: B) 20

Explanation:

Let the initial number of persons be x. Then,

16x + 20 * 15 = 15.5 (x + 20) <=> 0.5x = 10 <=> x = 20.

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Q:

The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero ?

A) 0 B) -1
C) 1 D) none of these
 
Answer & Explanation Answer: A) 0

Explanation:

Average of 20 numbers = 0. 

 

Sum of 20 numbers = (0 * 20) = 0. 

 

It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (- a).

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Q:

The average age of 36 students in a group is 14 years. When teacher's age is included to it, the average increases by one. What is the teacher's age in years ?

A) 35 years B) 45 years
C) 51 years D) 54 years
 
Answer & Explanation Answer: C) 51 years

Explanation:

Age of the teacher = (37 * 15 - 36 * 14) years = 51 years.

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Q:

The average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person ?

A) 70 kg B) 75 kg
C) 80 kg D) 85 kg
 
Answer & Explanation Answer: D) 85 kg

Explanation:

Total weight increased = (8 x 2.5) kg = 20 kg.

Weight of new person = (65 + 20) kg = 85 kg.

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Q:

The average of six numbers is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. What is the average of the remaining two numbers ?

A) 3.6 B) 4.6
C) 6.5 D) 7.3
 
Answer & Explanation Answer: B) 4.6

Explanation:

 Sum of the remaining two numbers = (3.95 * 6) - [(3.4 * 2) + (3.85 * 2)]

                                                   = 23.70 - (6.8 + 7.7) = 23.70 - 14.5 = 9.20.

Required average = (9.2 / 2) =  4.6.

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Q:

Of the four numbers, whose average is 60, the first is one-fourth of the sum of the last three. The first number is :

A) 17 B) 29
C) 36 D) 48
 
Answer & Explanation Answer: D) 48

Explanation:

Let the first number be x,

Then, sum of the four numbers = x + 4x = 5x.

so,  5x/4 = 60 or x = (60 * 4) / 5 = 48.

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116 37606
Q:

A cicketer bas a certain average for 10 innings, In the eleventh inning, he scorod 108 runs, thereby increasing his average by 6 runs. His new average is :

A) 44 runs B) 46 runs
C) 48 runs D) 49 runs
 
Answer & Explanation Answer: C) 48 runs

Explanation:

Let average for 10 innings be x. Then,

(10x + 108)/11 = x + 6 => 11x + 66 = 10x + 108  =>  x = 42.

New average = (x + 6) = 48 runs.

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