A) 1984 | B) 1863 |

C) 1900 | D) 2500 |

Explanation:

**NOTE:** When an year leaves a remainder 0 when divided by 4,then it is a leap year.

Here, 1984 divided by 4 leaves a remainder 0.

So, answer 1984 (366 days => leap year)

A) Monday | B) Wednesday |

C) Thursday | D) Tuesday |

Explanation:

We know that,

Odd days --> days more than complete weeks

Number of odd days in 400/800/1200/1600/2000 years are **0.**

Hence, the number of odd days in first 1600 years are 0.

Number of odd days in 300 years = 1

Number of odd days in 49 years = **(12 x 2 + 37 x 1) = 61 days = 5 odd days**

Total number of odd days in 1949 years = **1 + 5 = 6 odd days**

Now look at the year 1950

Jan 26 = 26 days = **3 weeks + 5 days = 5 odd days**

Total number of odd days = **6 + 5 = 11 => 4 odd days**

**Odd days :- **

0 = sunday ;

1 = monday ;

2 = tuesday ;

3 = wednesday ;

4 = thursday ;

5 = friday ;

6 = saturday

Therefore, **Jan 26th 1950** was **Thursday.**

A) October, December | B) April, November |

C) June, October | D) April, July |

Explanation:

If the period between the two months is divisible by 7, then that two months will have the same calender .

Now,

(a). October + November = 31 + 30 = 61 (not divisible by 7)

(b). Apr. + May + June + July + Aug. + Sep. + Oct. = 30 + 31 + 30 + 31 + 31 +30 + 31 = 213 (not divisible by 7)

(c). June + July + Aug. + Sep. = 30 + 31 + 31 + 30 = 122 (not divisible by 7)

(d). Apr. + May + June = 30 + 31 + 30 = 91 (divisible by 7)

Hence, April and July months will have the same calendar.

A) 31523500 sec | B) 315360000 sec |

C) 315423000 sec | D) 315354000 sec |

Explanation:

We know that,

1 year = 365 days

1 day = 24 hours

1 hour = 60 minutes

1 minute = 60 seconds.

Then, 1 year = 365 x 24 x 60 x 60 seconds.

= 8760 x 3600

1 year = 31536000 seconds.

Hence, **10 years = 31536000 x 10 = 315360000 seconds.**

A) Saturday | B) Sunday |

C) Friday | D) Thursday |

Explanation:

The day of the week repeats every 7 days.

Given today is Friday. Again Friday is repeated on the 7th day, 14th,... on 7 multiple days.

Hence, Friday is on the 63rd day, as 63 is multiple of 7.

Now, the required day of the week on the 65th day is **Sunday.**

A) same day | B) previous day |

C) next day | D) None |

Explanation:

We know that the day repeats every 7 days, 14 days, 21 days,...

So if today is Monday, after 7 days it is again Monday, after 14 days again it is Monday.

Hence, after 2 weeks i.e, 14 days the day repeats and is the same day.

A) 22 | B) 23 |

C) 24 | D) 25 |

Explanation:

Calculating Age has 2 conditions. Let your Birthday is on January 1st.

1. If the month in which you are born is completed in the present year i.e, your birthday, then

Your Age = Present year - Year you are born

As of now, present year = 2018

**i.e, Age = 2018 - 1995 = 23 years.**

2. If the month in which you are born is not completed in the present year i.e, your birthday, then

Your Age = Last year - Year you are born

As of now, present year = 2018

**i.e, Age = 2017 - 1995 = 22 years.**

On carefully inspecting this question, one can understand that there are two days which are important and these are:

*A. My Birthday.*

*B. The day when I am making this statement.*

If you think for a while, you will understand that such statements can be made only around the year’s end. So, if my birthday is on **31 December**, then I will be making this statement on **1 January**.

I will further explain using the following example:

1. Consider that **today** is **01 January 2017**.

2. Then, **the day before yesterday** was **30 December 2016 **and according to the question I was **25 **then.

3.** Yesterday **was **31 December 2016**, which happens to be my birthday too (Woohoo!), and my age increases by one to become **26**.

4. I will turn **27 **on my birthday this year (*31 December 2017*).

5. I will turn **28 **on my birthday next year (31 December 2018).

Now, if you read the question again, it will make more sense:

The **day before yesterday**(*30 December 2016*), I was 25 years old and **next year**(*31 December 2018*) I will be 28.

A) 2023 | B) 2027 |

C) 2029 | D) 2022 |

Explanation:

**How to find the years which have the same Calendars :**

**Leap year** calendar repeats every** 28 years.**

Here 28 is distributed as 6 + 11 + 11.

**Rules:**

a) If given year is at 1st position after Leap year then next repeated calendar year is **Givenyear+6**.

b) If given year is at 2nd position after Leap year then next repeated calendar year is **Givenyear+11**.

c) If given year is at 3rd position after Leap year then next repeated calendar year is **Givenyear+11**.

Now, the given year is 2018

We know that 2016 is a Leap year.

2016 2017 2018 2019 2020

**Lp Y 1st 2nd 3rd ** **Lp Y**

Here 2018 is at 2 nd position after the Leap year.

According to rule b) the calendar of 2018 is repeated for the year is **2018 + 11 = 2029.**