Common Admission Test (CAT) Questions and Answers with Explanation

Q:

A milkman has 20 liters of milk. If he mixes 5 liters of water, which is freely available, in 20 liters of pure milk. If the cost of pure milk is Rs. 18 per litre, then the profit of the milkman, when he sells all the mixture at cost price, is:

A) 20%	B) 25%
C) 33.33%	D) 18%

Answer & Explanation Answer: B) 25%

Explanation:

When the water is freely available and all the water is sold at the price of the milk, then the water gives the profit on the cost of 20 litres of milk.

Since, the profit % = $\frac{P r o f i t}{C o s t P r i c e} x 100$

Therefore, profit percentage = $\frac{5}{20} x 100$ = 25%

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Filed Under: Profit and Loss
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44 14230

Q:

Protagonist is to heroine as clothing is to

A) Jeans	B) Villain
C) Hero	D) Shopping

Answer & Explanation Answer: A) Jeans

Explanation:

Protagonist and heroine are synonums to each other. Similarly, clothing and jeans are synonyms to each other in the given options.

Hence, Protagonist is to heroine as clothing is to jeans.

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Filed Under: Analogy
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2 14220

Q:

If $\log_{7} (2)$ = m, then $\log_{49} (28)$ is equal to ?

A) 1/(1+2m)	B) (1+2m)/2
C) 2m/(2m+1)	D) (2m+1)/2m

Answer & Explanation Answer: B) (1+2m)/2

Explanation:

$\log_{49} (28) = \frac{1}{2 \log_{7} (7 \times 4)}$

= $\frac{1}{2} + \frac{1}{2} (2 \log_{7} (2))$
= $\frac{1}{2} + \log_{7} (2)$
= $\frac{1}{2} + m$
= $\frac{1 + 2 m}{2}$ .

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Filed Under: Logarithms
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63 14210

Q:

In a row of thirty boys, R is fourth from the right end and W is tenth from the left end . How many boys are there between R and W?

A) 15	B) 16
C) 17	D) can't be determined

Answer & Explanation Answer: B) 16

Explanation:

W = 10th from the left

R = 4th from the right = (30 - 4 + 1= ) 27th from left

No of boys between R and W = (27 - 10) - 1 = 16

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Filed Under: Number, Ranking and Time Sequence Test
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Q:

Ashtadhyayi was written by

A) Ved vysa	B) Panini
C) Shukadeva	D) Balmiki

Answer & Explanation Answer: B) Panini

Explanation:

Ashtadhyayi was written by Panini. He was a Sanskrit grammarian who gave a comprehensive and scientific theory of phonetics, phonology, and morphology. Panini was born in Shalatula, a town near to Attock on the Indus river in present day Pakistan.

Ashtadhyayi_was_written_by1565176023.jpg image

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Filed Under: Indian History
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Q:

Lagaan is levied on the 60% of the cultivated land. The revenue department collected total Rs. 3,84,000 through the lagaan from the village of Sukhiya. Sukhiya, a very rich farmer , paid only Rs.480 as lagaan. The percentage of total land of Sukhiya over the total taxable land of the village is:

A) 0.15%	B) 15%
C) 0.125%	D) None of these

Answer & Explanation Answer: D) None of these

Explanation:

Total land of Sukhiya = 480x/0.6 = 800x

Cultivated land of village = 384000x

Required percentage = $\frac{800 x}{384000} x 100 = 0.20833$

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Filed Under: Percentage
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Q:

Rs. 2600 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/2:1/3:1/4 ?

A) 600	B) 300
C) 150	D) 75

Answer & Explanation Answer: A) 600

Explanation:

1/2:1/3:1/4 = 6:4:3

As the difference is 3

=> 3/13x2600 = 600

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Filed Under: Ratios and Proportions
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Q:

There are 6561 balls are there out of them 1 is heavy. Find the minimum number of times the balls have to be weighted for finding out the heavy ball ?

A) 2414	B) 204
C) 87	D) 8

Answer & Explanation Answer: D) 8

Explanation:

Suppose there are 9 balls

Let us give name to each ball B1 B2 B3 B4 B5 B6 B7 B8 B9

Now we will divide all the balls into 3 groups.

Group1 - B1 B2 B3

Group2 - B4 B5 B6

Group3 - B7 B8 B9

Step1 - Now weigh any two groups. Let's assume we choose Group1 on left side of the scale and Group2 on the right side.

So now when we weigh these two groups we can get 3 outcomes.

Weighing scale tilts on left - Group1 has a heavy ball.
Weighing scale tilts on right - Group2 has a heavy ball.
Weighing scale remains balanced - Group3 has a heavy ball.
Lets assume we got the outcome as 3. i.e Group 3 has a heavy ball.

Step2 - Now weigh any two balls from Group3. Lets assume we keep B7 on left side of the scale and B8 on right side.

So now when we weigh these two balls we can get 3 outcomes.

Weighing scale tilts on left - B7 is the heavy ball.
Weighing scale tilts on right - B8 is the heavy ball.
Weighing scale remains balanced - B9 is the heavy ball.
The conclusion we get from this Problem is that each time weigh. We element 2/3 of the balls.

As we came to conclusion that Group3 has the heavy ball from Step1, we remove 6 balls from the equation i.e (2/3) of 9.

Simillarly we do the ame thing for the Step2.

Now going with this conclusion. We have 6561 balls.

Step - 1

Divided into 3 groups

Group1 - 2187Balls

Group2 - 2187Balls

Group3 - 2187Balls