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Q:

Ravi and Ramu are partners in a business.Ravi contributes 1/6 of the capital for 16 months and Ramu received 2/3 of the profit. For how long Ramu's money was used ?

A) 11 months B) 10 months
C) 9 months D) 8 months
 
Answer & Explanation Answer: D) 8 months

Explanation:

Let the total Profit be Z.
Ramu's profit share is 2/3 of profit (i.e 2Z/3)
Ravi's profit is (Z-2Z/3) =Z/3
Hence the profit ratio is , Ravi : Ramu = Z/3 : 2Z/3 = 1:2

Let total Capital be Rs.X and Ramu has contributed for Y months.Since Ramu's profit share is 2/3, his invest share will be 2/3 in capital.

Ravi's invest for 16 months / Ramu's invest for Y months = Ravi's profit share / Ramu's profit share
i.e. (X/6 x 16) / (2X/3 x Y) = 1/2

Solving the above equation, we get Y = 8.
So Ramu's money has been used for 8 months.

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Filed Under: Partnership
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5 8629
Q:

P and Q were assigned to do a work for an amount of 1200. P alone can do it in 15 days while Q can do it in 12 days. With the help of R they finish the work in 6 days. Find the share of R ?

A) 120 B) 240
C) 360 D) 180
 
Answer & Explanation Answer: A) 120

Explanation:

1/15 + 1/12 + 1/R = 1/6, we got R = 60 (it means R will take 60 days to complete the work alone)


so ratio of work done by P:Q:R = 1/15 : 1/12 : 1/60 = 5 : 4 : 1


so R share = (1/10) x 1200 = 120.

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Filed Under: Time and Work
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5 8622
Q:

How many rectangles can be drawn with 36 cm as the perimeter, given that the sides are positive integers in cm?

A) 8 B) 9
C) 10 D) 11
 
Answer & Explanation Answer: B) 9

Explanation:

Perimeter = 36


⇒ 2 ( l + w ) = 36


⇒ l + w = 18


Since length and width are positive integers in centimeters.

Therefore, possible dimensions are :


( 1, 17 )cm , ( 2, 16 ) cm , ( 3, 15 ) cm, (4 , 14) cm, ( 5,13) cm, ( 6, 12) cm , ( 7, 11) cm, ( 8, 10 ) cm, ( 9, 9) cm.


Hence, there are 9 rectangles.

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Filed Under: Arithmetical Reasoning
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12 8622
Q:

If sum of upstream and downstream speed of a boat is 82 kmph, and the boat travels 105 km. upstream in 3 hr, Find the time taken by boat to cover 126 km downstream. 

A) 2.8 hrs B) 2.7 hrs
C) 2.6 hrs D) 2.5 hrs
 
Answer & Explanation Answer: B) 2.7 hrs

Explanation:

Let Speed of boat in still water = b

Let Speed of still water = w

Then we know that,

Speed of Upstream = U = boat - water

Speed of Downstream = D = boat + water

Given, U + D = 82

b - w + b + w = 82

2b = 82

=> b = 41 kmph

From the given data,

41 - w = 105/3 = 35

w = 6 kmph

Now,

b + w = 126/t

=> 41 + 6 = 126/t

=> t = 126/47  = 2.68 hrs.

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Filed Under: Boats and Streams
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21 8620
Q:

If Hema walks at 12 km/hr instead of 8 km/hr, she would have walked 20 km more. The actual distance travelled by Hema is ?

A) 40 kms B) 30 kms
C) 46 kms D) 32 kms
 
Answer & Explanation Answer: A) 40 kms

Explanation:

Let the actual distance travelled be x km.
Then x/8=(x+20)/12
=> 12x = 8x + 160
=> 4x = 160
=> x = 40 km.

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Filed Under: Time and Distance
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5 8618
Q:

Who is known as Deenbandhu?

A) Vinoba Bhave B) Chitranjan das
C) C. N. Annadurai D) C. F. Andrews
 
Answer & Explanation Answer: D) C. F. Andrews

Explanation:

C. F. Andrews - Charles Freer Andrews was known as Deenbandhu. He was given this name by Mahathma Gandhi for his contributions towards Indian independence. 

 

Who_is_known_as_Deenbandhu1556519119.png image

 

Deenbandhu means a friend of the poor.

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Filed Under: Famous Personalities
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3 8613
Q:

Plane is to locomotive as pilot is to

A) flight B) helicopter
C) engineer D) None of the above
 
Answer & Explanation Answer: C) engineer

Explanation:

Plane and locomotive are synonyms to each other, Similarly, pilot and flight engineer are synonyms to each other. 

 

 

 

Hence, plane is to locomotive as pilot is to engineer.

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Filed Under: Analogy
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7 8611
Q:

The length of a rope in meter by which a cow must be tethered in order that she may be able to graze an area of 2826 sq.m is ?

A) 15 mts B) 30 mts
C) 24 mts D) 36 mts
 
Answer & Explanation Answer: B) 30 mts

Explanation:

The cow can graze an area of 2826 sq.m i.e it is able to cover area of circle of 2826 sq.m

 

Therefore, πr2 =2826
r2 =(2826×7/22) = 899.18 = 900
r = 30 m.

 

Therefore, the radius of the circle implies the length of the rope = 30 mts.

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Filed Under: Area
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9 8607