CAT Questions

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Let investment in each case be Rs. (143 x 117).

Income in 1st case = Rs.11143 x 143 x 117 = Rs. 1287.
Income in 2nd case = Rs.394×117 x 143 x 117= Rs. 1394.25

Clearly, 9 3/4% stock at 117 is better.

Let CP = 100,
42 % increase => SP = 142
10 % discount in SP => ((142 x 10)/100) = 14.2
So 1st SP = (142 - 14.2) = 127.8, again 12 % discount in 1st SP ((127.8 x 11)/100) = 14.058
2nd SP = (127.8 - 14.058) = 113.742,
So finally CP = 100, SP = 113.742, => gain = 13.742%.

That which cannot be conquered is called as Invincible.

One who speaks less is called as Reticent.

A pardonable offence is called as Venial.

The given figure can be labelled as shown :

The spaces P, Q and R have to be shaded by three different colours definitely (since each of these three spaces lies adjacent to the other two).
Now, in order that no two adjacent spaces be shaded by the same colour, the spaces T, U and S must be shaded with the colours of the spaces P, Q and R respectively.
Also the spaces X, V and W must be shaded with the colours of the spaces S, T and U respectively i.e. with the colours of the spaces R, P and Q respectively. Thus, minimum three colour pencils are required.

A Dome-shaped, muscular and membranous structure that separates as a partition of the thoracic and abdominal cavities is Diaphragm. 

Thoracic or chest cavity ::  It is the cavity where the heart and lungs are present. It is the second largest hallow space in the body.It also has vertebral column, ribs, breast bone,...

Abdominal cavity :: It is the cavity where the digestive tract, liver, kidneys, the spleen, pancreas,... are located. It is the largest hallow space of the body.

Just as tiles in mosaic make a pattern, so also the knots in a piece of macrame make a pattern.

Hence, Tile : Mosaic :: Knot : Macrame.

let 't' be the time after which they met since L starts.

Given K is 50% faster than L

50 t + 1.5*50(t-1) = 300

50 t +75 t = 300 + 75

t = 375 / 125 = 3 hrs past the time that L starts

So they meet at (9 + 3)hrs = 12:00 noon.

Let the initial amount of honey in the jar was k, then

 512 = k1 - 154 or 512 = k454 

 => k = 512 × 625256 

=> k = 1250

 Hence initially the honey in the jar = 1.25 kg