CAT Questions

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A bud is an undeveloped or embryonic shoot and may be specialized to develop flowers. Similarly, Seed is undeveloped and may be developed into a plant.

Hence, Flower : Bud :: Plant : Seed.

Number of applicants = 5
On a day, only 1 leave is approved.
Now favourable events =  1 of 5 applicants is approved
Probability that Laxmi priya's leave is granted = 1/5.

Assume first child (the youngest) get = Rs. x

According to the question ;
each son having Rs. 30 more than the younger one

Second child will get = Rs. x + 30
Third child will get = Rs. x + 30 + 30 = x + 60
Forth child will get = Rs. x + 30 + 30 + 30 = x + 90
Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120

Total amount they got = Rs. 2000

x + (x+30) + (x+60) + (x+90) + (x+120) = 2000
5x + 300 = 2000
5x = 1700
x = Rs. 340
So the youngest child will get Rs. 340.

The flow of information through MIS - Management Information System is Need dependent.

The backbone of any organization is Information. The information of MIS comes from both internal and external sources.

1ST SERIES = M J G... It decreasing by 3 alphabets.
2ND SERIES = N Q... It increasing by 3 alphabets.

M N J Q G T...

Computer memory - ROM is essentially empty. ROM is a Read Only Memory which cannot be retrieve.