AIEEE Questions

Q:

Kalyan purchased a Maruti van for Rs. 1,96,000 and the rate of depreciation is 14(2/7) % per annum. Find the value of the van after two years ?

A) Rs. 1,24,000 B) Rs. 1,44,000
C) Rs. 1,32,000 D) Rs. 1,62,000
 
Answer & Explanation Answer: B) Rs. 1,44,000

Explanation:

Value of Maruti Van, V1 = Rs. 1,96,000
Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 years
Let V2 is the value after depreciation.

V2 = V11 - r100t
V2 = 196001 - 10071002

V2 = 196000(6/7)(6/7)

V2 = (196000x36)/49 = Rs. 1,44,000.

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Q:

Group the given figures into three classes using each figure only once.

3_201484718690.png image

A) 1,3,5 ; 2,4,7 ; 6,8,9 B) 1,5,7 ; 2,3,6 ; 4,8,9
C) 1,3,5 ; 2,6,7 ; 4,8,9 D) 1,6,9 ; 2,4,7 ; 3,5,8
 
Answer & Explanation Answer: D) 1,6,9 ; 2,4,7 ; 3,5,8

Explanation:

1, 6, 9 are figures which are half shaded by slanting lines.
2, 4, 7 are all divided into equal parts (either three or four parts) by straight lines and also have a black circle at the centre.
3, 5, 8 have similar designs and have their four corners shaded black.

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Q:

A person lends Rs. 1540 for five years and Rs. 1800 for four years. If he gets Rs. 1788 as interest on both amounts, what is the rate of interest ?

A) 14.5% B) 11%
C) 12% D) 10.5%
 
Answer & Explanation Answer: C) 12%

Explanation:

Let the interest rate be r%

We know that,

S.I = PTR/100

=> (1540 x 5 x r)/100  +  (1800 x 4 x r)/100 = 1788

=> r = 178800/14900 = 12%

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Q:

How many birthdays does the average person have?

Answer

Any person can have only 1 birthday i.e, the day he was born. And every year we celebrate it's anniversaries.

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Q:

Ishikha got married 9 years ago. Today her age is 4/3 times her age at the time of marriage. At present her daughter’s age is one-sixth of her age. What was her daughter’s age three years ago?

A) 4 years B) 3 years
C) 2 years D) 1 year
 
Answer & Explanation Answer: B) 3 years

Explanation:

Let Ishika and her daughter present ages be p and q

 From the given data, 

p = 4/3(p - 9)

 => p = 36 years 

Hence, Ishika's present age = 36 years and

Her daughter's present age = 1/6 x 36 = 6 years 

Now, required her daughter’s age three years ago = 6 - 3 = 3 years.

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Q:

Which sport is played on the largest pitch?

A) Golf B) Cricket
C) Polo D) Football
 
Answer & Explanation Answer: C) Polo

Explanation:

Polo is the sport which is played in the largest pitch.

which_sport_is_played_on_the_largest_pitch1542950688.jpg image

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Q:

Which sample of matter is a mixture?

A) KBr (S) B) NaCl (L)
C) K (S) D) NaCl (Aq)
 
Answer & Explanation Answer: D) NaCl (Aq)

Explanation:

Mixtures are combination of two or more substances physically which can be separated in to the original.

Matter can be breakdown into two categories. 

1) Pure substances 

2) Mixtures

 

Here in the given options, options A, B, C are pure substances as they are indicated as S & L in brackets. Option D) is an aqueous solution, that can be dissolved in water.

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Q:

Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 56, what will be the sum of the highest number and the lowest number?

A) 120 B) 160
C) 80 D) 60
 
Answer & Explanation Answer: A) 120

Explanation:

Let the three numbers be x, y, z.

From the gien data,

x = 2y ....(1)

x = z/2 => z = 2(2y) = 4y .....(From 1)  ...........(2)

Given average of three numbers = 56

Then,

 

x + y + z3 = 562y + y + 4y3 = 56  (From 1 & 2)7y = 56 x 3y = 24

Now,

x = 2y => x = 2 x 24 = 48

z = 4y = 4 x 24 = 96

 

Now, the highest number is z = 96 & smallest number is y = 24

 

Hence, required sum of highest number and smallest number

= z + y

= 96 + 24

= 120.

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