AIEEE Questions

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The Chipko movement or Chipko Andolan refers to a forest conservation movement or deforestation. In modern india, it began in 1973 in the state of Uttar Pradesh (now Uttarakhand). Sunderlal Bahuguna and 84 villagers risked their lives to protect the forest trees from being felled on the order of the maharaja (king) and went on to become a rallying point for many future environmental movements all over the world it created a precedent for starting of nonviolent protest in India, and its success meant that the world immediately took notice of this non violent movement, which was to inspire in time many such eco-groups by helping to slow down the rapid deforestation, expose vested interests, increase ecological awareness, and demonstrate the viability of people power. Above all, it stirred up the existing civil society in India, which began to address the issues of tribal and marginalized people.

Chipko type movement dates back to 1730 AD when in a khejarli village of Rajasthan, 363 people sacrificed their lives to save khejari trees.

The given series follows,

2

2 x 2 = 4

4 x 3 = 12

12 x 4 = 48

48 x 5 = 240.

Given height of the conical tent = 3 m

Diameter = 10 => Radius = D/2 = 10/2 = 5 m 

Now, as the tent is in the conical form

Volume of the conical tent = πr2h3 

=> (22 x 5 x 5 x 3) / (7 x 3) 

= 22 x 25/7 

= 78.54 cu.m 

Given each person requires 3.92 cu.m of air 

=> Number of persons can be seated in the tent = 78.54/3.92 = 20.03 =~ 20

Controlled railroad crossing includes warning signs, red lights and railway gates, whereas absence of all of these warning signs like red lights and gates includes uncontrolled railroad crossings. 

Unlike Mitosis, Meiosis results in the formation of 4 Genetically different cells.

Meiosis results in the formation of 4 Haploid daughter cells from one Diploid parent cell.

Let the three parts M, N, O.
Then, M:N = 2:3 and N:O = 5:8
= (5 x 3/5) : (8 x 3/5) = 3:24/5

M:N:O = 2:3:24/5

= 10:15:24 => N = 98 x 15/49 = 30.

In H2SO4,

Hydrogen has a charge of +2, with each hydrogen has +1.

Oxygen has  a charge of -8, with each oxugen has -2.

Total charge = (2 - 8) = -6

Therefore, the Oxidation number of Sulphur S is '+6' because to make the compound stable.

Here by trial and error method, we can obseve that

404404 = 404 x 1001; 415415 = 415 x 1001, etc.

So, any number of this form is divisible by 1001.