AIEEE Questions

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Meiosis ::

Meiosis is a type of cell division that reduces the chromosome number by half in daughter cells, creating four haploid cells, each genetically distinct from the parent cell that gave rise to them.

Why it is called as Reduction Division ::

1. As the Meiosis division process involves in reduction of chromosome number in the daughter cells to half the number in the parent cell, this process is called Reduction Division.
Meiosis creates gametes (egg and sperm cells).

2. The resulting gametes have 23 new chromosomes, one member of each of the 23 pairs, representing unique combinations of the original maternal and paternal copies.

Wimbledon Tournament in the city London, is the prestigious and the oldest tournament in the world.

Let the side of the square be 's' cm

length of rectangle = (s+5) cm

breadth of rectangle = (s-3)cm

(s+5) (s-3) = 

s2 - 5s - 3s - 15 = s2 

2s = 15

Perimeter of rectangle = 2(L+B) = 2(s+5 + s–3) = 2(2s + 2)

= 2(15 + 2) = 34 cm 

IUPAC stands for International Union of Pure and Applied Chemistry.

A chemical nomenclature is a set of rules to generate systematic names for chemical compounds. The nomenclature used most frequently worldwide is the one created and developed by the International Union of Pure and Applied Chemistry (IUPAC).

Rate of her upstream = 12/2.5 = 4.8 km/hr

Then, ATQ

Rate of downstream = 4.8 x 3 = 14.4 km/hr

Hence, the distance she covers downstream in 5 hrs = 14.4 x 5 = 72 kms.

Total quantity of sugar = 45 + 30 = 75

Gain or loss can be calculated as

9.75 x 75 - (30 x 9 + 45 x 10)

= 731.25 - 720

= 11.25

Hence, in the overall transaction, Rishi got Rs. 11.25 gain.

Okhla Bird Sanctuary is located in Uttar Pradesh.

Okhla Bird Sanctuary is a bird sanctuary at the Okhla barrage over Yamuna River. It is situated in Noida, Gautam Buddh Nagar district, on Delhi-Uttar Pradesh state border and known as a haven for over 300 bird species.

Here, S = {1, 2, 3, 4, ...., 19, 20}=> n(s) = 20
Let E = event of getting a multiple of 4 or 15
=multiples od 4 are {4, 8, 12, 16, 20}
And multiples of 15 means multiples of 3 and 5
= {3, 6 , 9, 12, 15, 18, 5, 10, 15, 20}.
= the common multiple is only (15).
=> E = n(E)= 6
Required Probability = P(E) = n(E)/n(S) = 6/20 = 3/10.