Bank Exams Questions

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Given total number of passengers in the bus = 45

First average weight of 45 passengers = 52 kgs

Average weight of 5 passengers who leave bus = 48

Average weight of 5 passengers who joined the bus = 54

Therefore, the net average weight of the bus is given by

$$\begin{gathered} = 45 x 52 - 5 x 48 + 5 x 5445 \\ = 237045 \\ = 1583 \\ = 52.66 kgs. \end{gathered}$$

Garbage truck.

It’s true, a garbage truck has 4 wheels and lots of flies because flies like garbage. Here flies means insects like houseflies, mosquitoes, ... It doesn't mean that it flies in the air.

% Change in Curved Surface Area is given by 

%Change in radius + %Change in height + %Change in radius × %Change in height 100  

⇒+20 + 15 + 20×15100 = 38%

Let the C.P be 'x'
Then, the selling price S.P = x - 16x/100
= 84x/100 = 21x/25
Now, if the S.P is 60 more, then the profit is 14%
=> 21x/25 + 60 = x + 14x/100
=> 114x/100 - 21x/25 = 60
=> (57 - 42)x/50 = 60
=> 15x/50 = 60
x = 3000/15 = 200

Therefore, the Cost price C.P = x = Rs. 200

 P1+20100n>2P⇔65n>2

 65×65×65×65>2

so, answer is 4 years

Let the price of each note book be Rs.x.

Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.

Hence xy = 300

=> y = 300/x

(x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy

=>5(300/x) - 10x - 50 = 0 => -150+x2+5x

multiplying both sides by -1/10x

=> x2+15x-10x-150=0

=> x(x + 15) - 10(x + 15) = 0

=> x = 10 or -15

As x>0, x = 10.

Ratio C1:C2 = 3:5 and C2:C3 = 7:11
So C1:C2:C3 = 21 : 35 : 55
Let the strength of three classes are 21x, 35x and 55x respectively, then
Given that 21x + 35x + 55x = 333
=> 111x = 333 or x=3
So strength of the class with highest number of students =55x = 55x3 = 165.

Given (2a + 3b)/(5a - 3b) = 23/5
=> 10a + 15b = 115a - 69b
=> 105a = 84b => 5a = 4b
a/b = 4/5 => a=4 & b=5
=> bxa = 5x4 = 20.