GATE Questions

Q:

A word arrangement machine, When given an input line of words, rearranges it in every step following a certain rule. Following is an illustration of an input line of words and various steps of rearrangement.


Input: gone are take enough brought station
Step 1: take gone are enough brought station
Step 2: take are gone enough brought station
Step 3: take are station gone enough brought
Step 4: take are station brought gone enough
And Step 4 is the last step for this input. Now, find out an appropriate step in the following question following the above rule.

Question:
Input: car on star quick demand fat
What will be the third step for this input ?

A) star car demand quick on fat B) star quick car demand on fat
C) star car quick demand on fat D) none of these
 
Answer & Explanation Answer: C) star car quick demand on fat

Explanation:

Obsrving the given arrangement, we find the following pattern:
If we arrange the words in the given input in the alphabetical order and then label them as 1,2,3,4,5,6, then the last step contains the words in the order 6,1,5,2,4,3. However, the position of only one word is alteredat each step.
Input:car on star quick demand fat
Step1: star car on quick demand fat
Step2: star car quick on demand fat
Step3: star car quick demand on fat

Hence, the answer is C

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Filed Under: Sequential Output Tracing
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22 8327
Q:

A train covered k km at 40 kmph and another 2k km at 20 kmph. Find the average speed of the train in covering the entire 3k km ?

A) 28 kmph B) 24 kmph
C) 26 kmph D) 32 kmph
 
Answer & Explanation Answer: B) 24 kmph

Explanation:

Total time taken = k/40 + 2k/20 hours

= 5k/40 = k/8 hours

Average speed = 3k/(k/8) = 24 kmph.

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Filed Under: Problems on Trains
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6 8317
Q:

Given that 100.48 = x,  100.70 = y and xz = y2,  then the value of z is close to ___ ?

A) 3.7 B) 2.7
C) 3.6 D) 2.9
 
Answer & Explanation Answer: D) 2.9

Explanation:

xz = y2        10(0.48z) = 10(2 x 0.70) = 101.40

 0.48z = 1.40

 z = 140/18 = 35/12 = 2.9 (approx.)

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Filed Under: Simplification
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10 8310
Q:

In what time will Rs. 3300 becomes Rs. 3399 at 6% per annum interest compounded half-yearly ?

A) Quarter months B) Half year
C) 2 years D) 1 year
 
Answer & Explanation Answer: B) Half year

Explanation:

3300 ----- 3% ↑ (1st time interval, 99) → 3399.

Here, time interval is given as half-yearly i.e. 6 months.

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Filed Under: Compound Interest
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3 8310
Q:

Find the C.I. on Rs. 15,225 for 9 months at 16% per annum compounded quarterly ?

A) Rs. 1911 B) Rs. 1909
C) Rs. 1901 D) Rs. 1907
 
Answer & Explanation Answer: C) Rs. 1901

Explanation:

P = Rs. 15225, n = 9 months = 3 quarters, R = 16% p.a. per quarter.

 

Amount = 15225x1+41003

 

= (15225 x 26/25 x 26/25 x 26/25) = Rs. 17126.05

 

=> C.I. = 17126 - 15625 = Rs. 1901.05.

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Filed Under: Compound Interest
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10 8303
Q:

How many rectangles can be drawn with 36 cm as the perimeter, given that the sides are positive integers in cm?

A) 8 B) 9
C) 10 D) 11
 
Answer & Explanation Answer: B) 9

Explanation:

Perimeter = 36


⇒ 2 ( l + w ) = 36


⇒ l + w = 18


Since length and width are positive integers in centimeters.

Therefore, possible dimensions are :


( 1, 17 )cm , ( 2, 16 ) cm , ( 3, 15 ) cm, (4 , 14) cm, ( 5,13) cm, ( 6, 12) cm , ( 7, 11) cm, ( 8, 10 ) cm, ( 9, 9) cm.


Hence, there are 9 rectangles.

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Filed Under: Arithmetical Reasoning
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12 8297
Q:

On a ruler's tombstone, it is said that one sixth of his life was spent in childhood and one twelfth as a teenager. One seventh of his life passed between the time he became an adult and the time he married; five years later, his son was born. Alas, the son died four years before he did. He lived to be twice as old as his son did. How old did the ruler live to be ?

A) 84 years B) 72 years
C) 82 years D) 64 years
 
Answer & Explanation Answer: A) 84 years

Explanation:

Let the age of ruler is x so that of son = x/2 (given)
Now according to the given condition
(x/6) + (x/12) + (x/7) + 5 + (x/2) + 4 = x
=> x = 84

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Q:

Hemavathi gets 3 marks for each right sum and loses 2 marks for each wrong sum. He attempts 35 sums and obtains 60 marks. The number of sums attempted correctly is ?

A) 23 B) 24
C) 25 D) 26
 
Answer & Explanation Answer: D) 26

Explanation:

Let, Hema attempted 'k' sum correctly, then

k x 3 -2 x(35-k) = 60
5k = 130
k = 26

so 26 correct sums.

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Filed Under: Simplification
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