GATE Questions

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Let the three parts M, N, O.
Then, M:N = 2:3 and N:O = 5:8
= (5 x 3/5) : (8 x 3/5) = 3:24/5

M:N:O = 2:3:24/5

= 10:15:24 => N = 98 x 15/49 = 30.

Given numbers are 585 546 514 404 206 369
Then interchanging the 1st and 3rd digits of the given numbers, we get
585 645 415 404 602 963
Now, arranging them in ascending order
963 645 602 585 415 404
Then the last second number is 415.

Given that Vishal is 24th from either end of the row i.e from two sides

  1 2 3 4 5 . . . . . .24 23 22 21 20 . . . . . 5 4 3 2 1 

  Here before Vishal there are 23 members and after Vishal there are 23 members

  = 23+1+23 --> 47 members in the row.

In H2SO4,

Hydrogen has a charge of +2, with each hydrogen has +1.

Oxygen has  a charge of -8, with each oxugen has -2.

Total charge = (2 - 8) = -6

Therefore, the Oxidation number of Sulphur S is '+6' because to make the compound stable.

Using Trial and error method,

we get the number of girls in the hall = 78

Let 'M' be the maximum marks in the examination.

Therefore, Madhu got 32% of M = 32M/100 = 0.32M
And Kumar got 42% of M = 42M/100 = 0.42M.
In terms of the maximum marks Kumar got 0.42M - 0.32M = 0.1M more than Madhu. ---- (1)

The problem however, states that Kumar got 16 marks more than the cut-off mark and Madhu got 8 marks less than the cut-off mark. Therefore, Kumar has got 16 + 8 = 24 marks more than Madhu. ---- (2)

Now, Equating (1) and (2), we get
0.1M = 24 => M = 24/0.1 = 240
'M' is the maximum mark and is equal to 240 marks.
We know that Madhu got 32% of the maximum marks.
Therefore, Madhu got 32 x 240/100 = 76.8 marks.
We also know that Madhu got 8 marks less than the cut-off marks.

Therefore, the cut-off marks will be 8 marks more than what Madhu got
= 76.8 + 8 = 84.8.

In first he got Rs. 990

But in second he lost Rs. 1980

So he lost Rs. 990.

Let Veena's weight = 1 kg

Sana's weight = 2 kg

Sneha's weight = 1.4 kg

Rina's weight = 1.8 kg

Now,according to the given data in the question,

1.8x100 = 1.4

x = 1.4 × 1001.8 = 7009 = 77 79.