GRE Questions

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9321 = 3 x 13 x 239 = 31 x 13 1 x 239 1 ; add one to all the powers ie.,

(1+1) x (1+1) x (1+1)= 8 ;

we get eight factors.

Days in 4 years => 

Let the first year is Normal year i.e, its not Leap year. A Leap Years occurs once for every 4 years.

4 years => 365 + 365 + 365 + 366(Leap year)

4 years => 730 + 731 = 1461

Therefore, Number of Days in 4 Years = 1461 Days.

1 + 1 = 121 = 1x1 1+1 1x1

1 + 2 = 134 = 1x1 1+2 2x2

2 + 2 = 444 = 2x2 2+2 2x2

3 + 2 = 954 = 3x3 3+2 2x2

3 + 3 = ?   

Similarly, 3x3 3+3 3x3 = 969

YEAR - 1 E

WEEK - 2 E

DAY - 0 E

Hence, the letter 'E', comes once in a year, twice in a week and never in a day.

Time = (100 x 81)/(450 x 4.5) years

= 4 years.

Resolving from the last , In the view of joel,
My father’s wife – mother
Only son of mother – himself i.e. joel
Daughter of john– daughter.

So Joel is Father of Mary.

Let the 1 day work of a boy=b and a girl=g, then
2b + g = 1/5 ---(i) and
b + 2g = 1/6 ---(ii)
On solving (i) & (ii), b=7/90, g=2/45
As payment of work will be in proportion to capacity of work and a boy is paid $ 28/week,
so a girl will be paid 28×245790 = 16 $.

Let the first number be K and second number be L
Then, 2K + 3L = 100.....(1)
3K + 2L = 120.......(2)
solving (1)&(2), we get
K = 32 and L = 12

Hence the largest number is 32.