Bank PO Questions and Answers with Explanation, Job Roles

Q:

What should be replaced in the place of '?' in the following series ?

JAK, KBL, LCM, MDN, ?

A) MEN	B) NEM
C) NEO	D) OEP

Answer & Explanation Answer: C) NEO

Explanation:

This is an alternating series in alphabetical order. The middle letters follow the order ABCDE. The first and third letters are alphabetical beginning with J. The third letter is repeated as a first letter in each subsequent three-letter segment.

Report Error

View Answer Report Error Discuss

Filed Under: Number Series
Exam Prep: Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO

6 44821

Q:

# 6 B G @ I L 7 3 H A % @ D F K E 8 J Q I * V T U 2 $ W

If all the numbers are dropped from the above arrangement which element will be fifth to the left of eleventh from the left?

A) I	B) H
C) T	D) None of these

Answer & Explanation Answer: D) None of these

Explanation:

Report Error

View Answer Report Error Discuss

Filed Under: Verbal Reasoning - Mental Ability
Exam Prep: Bank Exams
Job Role: Bank PO

3 44783

Q:

The difference between compound interest and simple interest on a sum for two years at 8% per annum, where the interest is compounded annually is Rs.16. if the interest were compounded half yearly , the difference in two interests would be nearly

A) Rs.24.64	B) Rs.21.85
C) Rs.16	D) Rs.16.80

Answer & Explanation Answer: A) Rs.24.64

Explanation:

For 1st year S.I =C.I.

Thus, Rs.16 is the S.I. on S.I. for 1 year, which at 8% is thus Rs.200

i.e S.I on the principal for 1 year is Rs.200

Principle = $R s . \frac{100 * 200}{8 * 1}$ = Rs.2500

Amount for 2 years, compounded half-yearly

$R s . [2500 * {(1 + \frac{4}{100})}^{4}] = R s . 2924.4$

C.I = Rs.424.64

Also, $S . I = R s . (\frac{2500 * 8 * 2}{100}) = R s . 400$

Hence, [(C.I) - (S.I)] = Rs. (424.64 - 400) = Rs.24.64

Report Error

View Answer Report Error Discuss

Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

121 44628

Q:

There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate

A) Rs.4972	B) Rs.3972
C) Rs.5972	D) Rs.2972

Answer & Explanation Answer: B) Rs.3972

Explanation:

Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.

R= $\frac{100 * 60}{100 * 6}$ =10% p.a

Now, P = Rs. 12000. T = 3 years and R = 10% p.a.

C.I= $R s . [12000 * {[1 + \frac{10}{100}]}^{3} - 1]$
=Rs.3972

Report Error

View Answer Report Error Discuss

Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

52 44455

Q:

Guess the next number in the given number series?

999, 990, 998, 991, 997, 992, ?

A) 996	B) 1000
C) 999	D) 1001

Answer & Explanation Answer: A) 996

Explanation:

The given number series 999, 990, 998, 991, 997, 992, ?

It follows a pattern that,

999

999 - 9 = 990

990 + 8 = 998

998 - 7 = 991

991 + 6 = 997

997 - 5 = 992

992 + 4 = 996

Hence, the next number in the given number series is 996.

Report Error

View Answer Report Error Discuss

Filed Under: Number Series
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO

8 44377

Q:

A school has four sections A, B, C, D of Class IX students.

1. If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context?

A. Half yearly examinations were more difficult.

B. Annual examinations were more difficult.

C. Both the examinations had almost the same difficulty level.

D. The two examinations cannot be compared for difficulty level.

2. How many students are there in Class IX in the school?

A. 336 B.189 C. 335 D. 430

3. Which section has the maximum pass percentage in at least one of the two examinations?

A. A Section B. B Section C. C Section D. D Section

4. Which section has the maximum success rate in annual examination?

A. A Section B. B Section C. C Section D. D Section

5. Which section has the minimum failure rate in half yearly examination?

A. A section B. B section C. C section D. D section

Half yearly examinations were more difficult.

If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context? - See more at: https://www.theonlinetestcentre.com/table-charts7.html#sthash.slrcbjro.dpuf

Answer

1. ANSWER : C

Explanation - Number of students who passed half-yearly exams in the school

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)
= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

2. ANSWER : D

Explanation - Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class:

= (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)

= 430.

3. ANSWER : D

Explanation- Pass percentages in at least one of the two examinations for different sections are:

For Section A = $\frac{14 + 6 + 64}{28 + 14 + 6 + 64} \times 100 = \frac{84}{112} \times 100$ % = 75%

For Section B = $\frac{12 + 17 + 55}{23 + 12 + 17 + 55} \times 100$ % = 78.5%

For Section C = $\frac{8 + 9 + 46}{17 + 8 + 9 + 46} \times 100$ %= 78.75%

For Section D = $\frac{13 + 15 + 76}{27 + 13 + 15 + 76} \times 100$ %= 79.39%

Clearly ,the pass percentage is maximum for Section D

4. ANSWER : A

Explanation - Total number of students passed in annual exams in a section

= [ (No. of students failed in half-yearly but passed in annual exams) + (No. of students passed in both exams) ] in that section

Success rate in annual exams in Section A= $\frac{14 + 64}{112} \times 100$ % = 69.64%

Similarly, success rate in annual exams in:

Section B = $\frac{12 + 55}{107} \times 100$ % = 62.62%

Section C = $\frac{8 + 46}{80} \times 100$ % = 67.5%

Section D = $\frac{89}{131} \times 100$ % = 67.94%

Clearly, the success rate in annual examination is maximum for Section A.

5. ANSWER : D

Explanation - Total number of failures in half-yearly exams in a section

= [ (Number of students failed in both exams) + (Number of students failed in half-yearly but passed in Annual exams) ] in that section

Failure rate in half-yearly exams in Section A %= 37.5 %

Similarly, failure rate in half-yearly exams in:

Section B = 32.71%

Section C = 31.25%

Section D = 30.53%

Clearly, the failure rate is minimum for Section D.

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)

= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

Workspace

Report Error

View answer Workspace Report Error Discuss

Subject: Table Charts Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

138 44175

Q:

A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at $6 \frac{1}{4}$ p.a for 2 years. Find his gain in the transaction per year

A) Rs. 112.50	B) Rs.150.25
C) Rs.167.50	D) Rs.170

Answer & Explanation Answer: A) Rs. 112.50

Explanation:

$g a i n i n 2 y e a r s = R s . [(5000 * \frac{25}{4} * \frac{2}{100}) - (\frac{5000 * 4 * 2}{100})]$

= Rs. (625 - 400)

= Rs. 225

$g a i n i n 1 y e a r = R s . (\frac{225}{2}) = 112.50$

Report Error

View Answer Report Error Discuss

Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

124 44089

Q:

The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

A) 20	B) 200
C) 300	D) 400

Answer & Explanation Answer: B) 200

Explanation:

Let length of plot = L meters, then breadth = L - 20 meters

and perimeter = 2[L + L - 20] = [4L - 40] meters

[4L - 40] * 26.50 = 5300

[4L - 40] = 5300 / 26.50 = 200

4L = 240

L = 240/4= 60 meters.

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

30 43971

Bank PO Questions

Quick Links