Bank PO Questions and Answers with Explanation, Job Roles

Q:

The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

A) 2520	B) 2420
C) 2320	D) 2620

Answer & Explanation Answer: A) 2520

Explanation:

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.
Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) = 2520 sq.m

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

29 27326

Q:

The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is ?

A) 8 kmph	B) 6 kmph
C) 7.5 kmph	D) 5.5 kmph

Answer & Explanation Answer: B) 6 kmph

Explanation:

Speed of the stream = 1
Motor boat speed in still water be = x kmph
Down Stream = x + 1 kmph
Up Stream = x - 1 kmph
[35/(x + 1)] + [35/(x - 1)] = 12
x = 6 kmph

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

70 27275

Q:

What annual payment will discharge a debt of Rs.7620 due in 3years at $16 \frac{2}{3}$ % per annum interest?

A) 5430	B) 4430
C) 3430	D) 2430

Answer & Explanation Answer: C) 3430

Explanation:

Let each installment be Rs.x. Then,

(P.W. of Rs.x due 1 year hence) + (P.W of Rs.x due 2 years hence) + (P.W of Rs. X due 3 years hence) = 7620.

$[\frac{x}{(1 + \frac{50}{3 x 100})}] + [\frac{x}{1 + {(\frac{50}{3 x 100})}^{2}}] + [\frac{x}{1 + {(\frac{50}{3 x 100})}^{3}}] = 7620$

$\frac{6 x}{7} + \frac{36 x}{49} + \frac{216 x}{343} = 7620$

$294 x + 252 x + 216 x = 7620 x 343$

=> x = 3430

Amount of each installment = Rs.3430

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

78 27175

Q:

52 C in a P?

Answer

52 C in a P represents 52 Cards in a Pack.

Similar to

12 S of the Z

5 C in an OF

Workspace

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Subject: Logic Puzzles Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE , TOEFL
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

67 27094

Q:

What is the least number of squares tiles required to pave the floor of a room 15.17 m long and 9.02 m broad?

A) 814	B) 714
C) 614	D) 713

Answer & Explanation Answer: A) 814

Explanation:

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.

Area of each tile = $(41 \times 41) c m^{2}$

Required number of tiles = $\frac{1517 \times 902}{41 \times 41}$ = 814

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

26 27063

Q:

In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm)

A) 80%	B) 70%
C) 75%	D) 62%

Answer & Explanation Answer: A) 80%

Explanation:

Water in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm.

After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm.

So % of water = 100 x 60/75 = 80%.

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Filed Under: Alligation or Mixture
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

40 27046

Q:

The area of a circular field is 13.86 hectares. Find the cost of fencing it at the rate of Rs. 4.40 per metre.

A) 2808	B) 3808
C) 4808	D) 5808

Answer & Explanation Answer: D) 5808

Explanation:

Area = (13.86 x 10000) sq.m = 138600 sq.m

${πR}^{2} = 138600 \Rightarrow R^{2} = 138600 \times \frac{7}{22} \Rightarrow R = 210 m$

Circumference = $2 {πR}^{2} = 2 \times \frac{22}{7} \times 210 = 1320 m$

Cost of fencing = Rs. (1320 x 4.40) = Rs. 5808.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

25 26974

Q:

A rectangular plot measuring 90 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed?

A) 65m	B) 45m
C) 55m	D) 56m

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