Bank PO Questions and Answers with Explanation, Job Roles

Q:

Water flows into a tank which is 200 m long and 150 m wide, through a pipe of cross-section (0.3m x 0.2m) at 20 km/h. In what time will the water level be 12m ?

A) 200 hrs	B) 240 hrs
C) 300 hrs	D) 270 hrs

Answer & Explanation Answer: C) 300 hrs

Explanation:

Volume of water collected in the tank in 1 hour

⇒ (0.3 × 0.2 × 20km × 1000mts) = 1200 m cubic

If after t hours, the water is at height of 12m,

1200t=200×150×12

⇒ t = 300 Hours.

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Filed Under: Pipes and Cistern
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

25 12701

Q:

Which one of the following began with the Dandi March ?

A) Civil disobedience Movement	B) Quit India Movement
C) Non-Cooperation Movement	D) Home rule Movement

Answer & Explanation Answer: A) Civil disobedience Movement

Explanation:

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Filed Under: Indian History
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

30 12693

Q:

A driver of auto rickshaw makes a profit of 20% on every trip when he carries 3 passengers and the price of petrol is Rs. 30 a litre. Find the % profit for the same journey if he goes for 4 passengers per trip and the price of petrol reduces to Rs. 24 litres ?

A) 68%	B) 80%
C) 75%	D) 100%

Answer & Explanation Answer: D) 100%

Explanation:

When 3 passengers income was 3x
expense= Rs.30
profit =20% of 30 = Rs.6
That means his earning is Rs.36. so that per passenger fare must be Rs.12.

When 4 passengers
earning = 12x4=Rs.48.
expense =Rs.24.
profit = Rs.24 = 100%

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Filed Under: Profit and Loss
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

19 12682

Q:

At an examination in which maximum marks are 500. P got 10% less than Q, Q got 25% more than R and R got 20% less than S. If P got 360 marks what percentage of marks was obtained by S ?

A) 77	B) 74
C) 80	D) 83

Answer & Explanation Answer: C) 80

Explanation:

Let marks obtained by S = M

R's marks = 0.80M

Q's marks = 1.25 (0.80M)

P's marks = (0.90) (1.25) (0.80M)

= 0.9M

But 0.9M = 360

M = ?

M = 400

Hence % of marks obtained by S

= 400/500 x 100 = 80%.

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

11 12679

Q:

Rajeev start a business with Rs. 10000, Deepu joins him after 2 month with 20% more investment than Rajeev, after 2 month Shakti joins him with 40% less than Deepu. If the profit earned by them at the end of the year is equal to the twice of the difference between investment of Rajeev and ten times the investment of Shakti. Find the profit of Rajeev ?

A) 50000	B) 48000
C) 38000	D) 40000

Answer & Explanation Answer: C) 38000

Explanation:

Here from the given information,

The ratio of investments of Rajeev, Deepu & Shakti is

R : D : S = (10000 × 12) : (12000 × 10) : (7200 × 8)

= 25 : 25 : 12

Now the Profit = 2 × (72000-10000) = 124000

Share of Rajeev = 124000 x 25/62 = 48000

Profit of Rajeev = 48000 - 10000 = 38000

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Filed Under: Partnership
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

21 12676

Q:

A trader marked the price of the T.V. 30% above the cost price of the T.V. and gave the purchaser 10% discount on the marked price, thereby gaining Rs.340. Find the cost price of the T.V ?

A) Rs. 2000	B) Rs. 1600
C) Rs. 2200	D) Rs. 2100

Answer & Explanation Answer: A) Rs. 2000

Explanation:

Let 'x' be the cost price.
Now Marked price = x + 30x/100 = 13x/10
10% discount = 10/100 x 13x/10 = 13x/100
Selling price = 13x/10 - 13x/100 = 117x/100
Given gain = 340
Here gain = 117x/100 - x = 17x/100 = 340 => x = Rs. 2000.

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

13 12662

Q:

Chief component of first generation computer was

A) Vacuum tubes	B) integrated circuits
C) transisters	D) None of the above

Answer & Explanation Answer: A) Vacuum tubes

Explanation:

chief_component_of_first_generation_computer_was1538216221.jpg image

The chief component in the first generation computers are Vacuum tubes.

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Filed Under: Computer
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

16 12651

Q:

Karthik read $\frac{6}{13}$ th of a book in 1st week and $\frac{5}{9}$ th of the remaining book in 2nd week. If there were 100 pages unread after 2nd week, how many pages were there in the book ?

A) 404	B) 415
C) 418	D) 420

Answer & Explanation Answer: C) 418

Explanation:

Let the total book be 1

Then, in the 1st week $\frac{6}{13}$ th of book is read

i.e remaining pages = $1 - \frac{6}{13} = \frac{7}{13}$

in 2nd week he read $\frac{5}{9}$ th of it

i.e $\frac{5}{9} \times \frac{7}{13} = \frac{35}{117}$
Remaining pages after 2nd week = $\frac{7}{13} - \frac{35}{117} = \frac{28}{117}$

But given remaining pages after 2nd week = 100

$\frac{28 x}{117} = 100$

--> x = 418

The total pages in the book are 418

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Filed Under: Decimal Fractions
Exam Prep: GATE , CAT , Bank Exams
Job Role: Bank PO , Bank Clerk

17 12640

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