**1. Answer : 4**

**Explanation : **Required ratio = $\frac{10+2+5}{10+15+10}=\frac{17}{35}\approx \frac{1}{2}=1:2$

**2. Answer : 1**

**Explanation : **

A to B Speed =$\frac{140\times 3}{5}$ = 84

B to C Speed = $\frac{91\times 3}{4}$ = 68.25

C to D Speed = $\frac{149\times 60}{103}$ = 86.796

D to E Speed = $\frac{88\times 3}{4}$ = 66

E to F Speed = $\frac{106\times 4}{5}$= 84.8

F to G Speed = $\frac{176}{2}$ = 88

G to h Speed = $\frac{110\times 4}{5}$= 88

Average speed of entire trip = $\frac{84+68.25+86.796+66+84.8+88+88}{7}$ =80.83

**3. Answer : 3**

**Explanation : **Total half time = 10 + 2 + 5 + 10 + 15 + 10 = 52

Total half time, if the train stops at each city for 50% more=$52\times \frac{150}{100}$=78

Train will arrive at city H after departing from city A = 18.25 + (78 - 52 )=18.25 + 26=18.51

**4. Answer : 2**

**Explanation : **Average speed = $\frac{84+68.25+86.796+66+84.8+88+88}{7}$=80.83=81 km/hr

**5. Answer : 1**

**Explanation : ** Required percentage of time = $\frac{1.40+1.20+1.43+1.20+1.15+2+1.15}{18.25-7}\times 100$= $\frac{10.23}{11.25}\times 100$ = 91.8 %

**1. Answer : 4**

**Explanation : **Required ratio =

**2. Answer : 1**

**Explanation : **A to B Speed = = 84

B to C Speed = = 68.25

C to D Speed = = 86.796

D to E Speed = = 66

E to F Speed = = 84.8

F to G Speed = = 88

G to h Speed = = 88

Average speed of entire trip = =80.83

**3. Answer : 3**

**Explanation : **Total half time = 10 + 2 + 5 + 10 + 15 + 10 = 52

Total half time, if the train stops at each city for 50% more = = 78

Train will arrive at city H after departing from city A = 18.25 + (78 - 52 ) = 18.25 + 26 = 18.51

**4. Answer : 2**

**Explanation : **Average speed = = 80.83 = 81 km/hr

**5. Answer : 1**

**Explanation : ** Required percentage of time =

=

= 91.8 %