The number of blueberries is equal to number of cups multiplied by 4 minus one left.

That is :

B = 9(C - 2) -> (1)

Then the number of blueberries will be equal to the number of cups times three plus one left.

That is :

B = 6C + 3 -> (2)

Now substitute the 1st and 2nd equations:

B = 9(C - 2)

B = 6C + 3

C = 7, B = 45.

Therefore Blueberries = 45 and cups = 7.

A) 12 | B) 6 |

C) 3 | D) 1 |

Explanation:

In the given puzzle, the logic behind is

9 = 72 => **9 x 8 = 72**

8 = 56 => **8 x 7 = 56**

7 = 42 => **7 x 6 = 42**

6 = 30 => **6 x 5 = 30**

5 = 20 => **5 x 4 = 20**

Similarly,

4 = 12 => **4 x 3 = 12**

3 = 6 => **3 x 2 = 6**

A) 9 | B) 15 |

C) 6 | D) 12 |

Explanation:

In the given puzzle, the logic is the product of the number and its preceeding number gives the result.

9 = **9 x 8** = 72

8 = **8 x 7** = 56

7 = **7 x 6** = 42

6 = **6 x 5** = 30

5 = **5 x 4** = 20

Similarly,

**3 = 3 x 2 = 6.**

A) 36 | B) 72 |

C) 84 | D) 96 |

Explanation:

Here in the given puzzle,

2 x (2 + 2) = 8

3 x (3 + 3) = 18

4 x (4 + 4) = 32

5 x (5 + 5) = 50

Similarly,

**6 x (6 + 6) = 72.**

A) 9 | B) 8 |

C) 7 | D) 6 |

Explanation:

Here by observing the figure,

we can complete the above incomplete cube with 2 cubes in 2 rows and 2 columns

=> 2 x 4 = 8.

Hence, with **8 small cubes** we can complete the cube.

A) 9 times | B) 10 times |

C) 1 time | D) 0 times |

Explanation:

How many times can you subtract 10 from 100, for this if we go through logically, it is only 1 time. For the first time if we subtract 10 from 100, then there will no 100 to subtract from.

Hence, it is only 1 time we can subtract 10 from 100.

From the assumption and trial and error method,

last three digits sum must leave the same digit as the answer. It is possible only if the answer must be units digit number leaving tens digit as carry.

And the possible 3rd digit is 5. Since 5 + 5 + 5 = 15

Now, 2nd step is 1 + x + x + x = 5

=> 3x = 4

It is possible with x = 8. 8 + 8 + 8 + 1 = 25 leaving 2 as carry.

Now, 3rd step is 2 + x + x + x = 5 => x = 1

Hence, the three dgits are 1, 8, 5.

**185 + 185 + 185 = 555. **

A) 4 | B) 8 |

C) 12 | D) 16 |

Explanation:

Here given that 9 = 63, 8 = 48, 7=35, ...

The given question follows a pattern that

**9 x (9 - 2) = 9 x 7 = 63**

**8 x (8 - 2) = 8 x 6 = 48**

**7 x (7 - 2) = 7 x 5 = 35**

Similarly, **4 x (4 - 2) = 4 x 2 = 8.**