18
Q:

# The solution of 3(2u + v) = 7 uv and 3(u + 3v) = 11 uv is _____

 A) u = 1, v = 0 B) u = 1, v = 3/2 C) u = 0, v = 3/4 D) u = 0, v = 1

Answer:   B) u = 1, v = 3/2

Explanation:

Using Trial and error method,

From the options  u = 1, v = 3/2 satisfies both the equations.

Q:

 A) 4X B) 2X C) 2X^2 D) X/2

Answer & Explanation Answer: C) 2X^2

Explanation:

Here the given expression,

is an algebraic expression. Here in this expression the terms are like terms. Now to add them, add their coefficients.

Here in the given expression, the like terms are two

Hence, adding their coefficients i.e, 1 + 1 = 2

Therefore,

= 2$X2$.

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0 194
Q:

5x - 6 = 3x - 8

Solve the above equation.

 A) 2 B) -1 C) -2 D) 1

Answer & Explanation Answer: B) -1

Explanation:

Given 5x - 6 = 3x - 8

5x - 3x = -8 + 6

2x = -2

=> x = -1.

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2 361
Q:

3 x 3 + 3 - 3 + 3 = ?

 A) 9 B) 12 C) -3 D) 3

Answer & Explanation Answer: B) 12

Explanation:

Using BODMAS law,

3 x 3 + 3 - 3 + 3 =

3 x 3 = 12

= 12 + 3 - 3 + 3

=  9 + 3

= 12

Hence, 3 x 3 + 3 - 3 + 3 = 12.

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4 372
Q:

What is x squared plus x squared?

 A) 4x B) 2x^2 C) x^4 D) 2x

Answer & Explanation Answer: B) 2x^2

Explanation:

In an algebraic expression, like terms are terms that contain the same variables raised to the same powers. Calculating x-squared plus x-squared is a matter of combining like terms.

Now x^2 + x^2 = 2x^2

Hence, x-squared plus x-squared is equal to 2 times x squared.

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1 326
Q:

What is

 A) 0 B) 42 C) 50 D) 57

Answer & Explanation Answer: C) 50

Explanation:

Given 7 + 7/7 + 7 x 7 - 7

By using BODMAS rule,

7 + 1 + 7 x 7 - 7

= 8 + 49 - 7

= 57 - 7

= 50.

Hence 7 + 7/7 + 7 x 7 - 7 = 50.

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3 582
Q:

Find the Value of ?

 A) 81 B) 77 C) 73 D) 89

Answer & Explanation Answer: D) 89

Explanation:

This can be done in a method called Approximation.

Now,

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7 546
Q:

Can you Solve  =

 A) 112 B) 56 C) 0 D) 98

Answer & Explanation Answer: A) 112

Explanation:

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9 473
Q:

The last two digits of $2151415$?

 A) 81 B) 61 C) 91 D) 51

Answer & Explanation Answer: D) 51

Explanation:

Unit digit of this expression is always 1 as the base ends with 1.

For the tenth place digit we need to multiply the digit in the tenth place of the base and unit digit of the power and take its unit digit.

i.e, tenth place digit in 2151 is 5 and

tenth place digit in power 415 is 1

And the units digit in the product of 5 x 1 = 5

Therefore, last two digits of $2151415$ is 51.

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7 946