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Q:

How many of the following numbers are divisible by 132?

264,396,462,792,968,2178,5184,6336

A) 4 B) 5
C) 6 D) 7

Answer:   A) 4



Explanation:

132 = 4 x 3 x 11, So if the number is divisible by all three numbers 4,3 and 11,then the number is divisible by 132 also.
264   => 4,3,11(/)
396   => 4,3,11(/)
462   => 11,3
792   => 4,3,11(/)
968   => 11,4
2178 => 11,3
5184 => 3,4
6336 => 4,3,11(/)
Required number of numbers=4.

Subject: Numbers
Related Questions
Q:

What smallest number should be added to 4456 so that the sum is completely divisible by 6 ?

A) 4 B) 3
C) 2 D) 1
 
Answer & Explanation Answer: C) 2

Explanation:

6)4456(742
42
--------
25
24
-------
16
12
-----
4
------
Required number = (6-4) = 2.

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25 23955
Q:

Which natural number is nearest to 8485, which is completely divisible by 75 ?

A) 8475 B) 8500
C) 8550 D) 8525
 
Answer & Explanation Answer: A) 8475

Explanation:

On dividing we get

75)8485(113
     75
     ------
       98
       75
      ------
       235
       225
      ------
         10
      ------
Required number = (8485-10)=8475.

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16 15475
Q:

What least number must be subtracted from 13601, so that the remainder is divisible by 87 ?

A) 23 B) 31
C) 29 D) 37
 
Answer & Explanation Answer: C) 29

Explanation:

87)13601(156
       87
       -----
       490
       435
        -----
        551
        522
         -----
         29
         -----
Required number is 29.

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191 45191
Q:

n is a whole number which when divided by 4 gives 3 as remainder. What will be the remainder when 2*n is divided by 4 ?

A) 3 B) 2
C) 1 D) 0
 
Answer & Explanation Answer: B) 2

Explanation:

Let n=4*q + 3. Then, 2*n = 8*q + 6 = 4(2*q + 1) + 2.
Thus when 2*n is divided by 4, the reminder is 2.

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22 12576
Q:

476 ** 0 is divisible by both 3 and 11.The non zero digits in the hundred's and ten's places are respectively:

A) 6 and 2 B) 8 and 2
C) 6 and 5 D) 8 and 5
 
Answer & Explanation Answer: D) 8 and 5

Explanation:

Let the number  be 476ab0 

 

476ab0 is divisible by 3 

=> 4 + 7 + 6 + a + b + 0 is divisible by 3

=> 17 + a + b is divisible by 3 ------------------------(i)

 

476ab0 is divisible by 11

[(4 + 6 + b) -(7 + a + 0)] is 0 or divisible by 11

=> [3 + (b - a)] is 0 or divisible by 11  --------------(ii)

 

Substitute the values of a and b with the values given in the choices and select the values which satisfies both Equation 1 and Equation 2.

 

if a=6 and b=2, 

17 + a + b = 17 + 6 + 2 = 25 which is not divisible by 3 --- Does not meet equation(i).Hence this is not the answer

 

if a=8 and b=2, 

17 + a + b = 17 + 8 + 2 = 27 which is divisible by 3 --- Meet equation(i)

[3 + (b - a)] = [3 + (2 - 8)] = -3 which is neither 0 nor divisible by 11---Does not meet equation(ii).Hence this is not the answer

 

if a=6 and b=5, 

17 + a + b = 17 + 6 + 5 = 28 which is not divisible by 3 --- Does not meet equation (i) .Hence this is not the answer

 

 

if a=8 and b=5, 

17 + a + b = 17 + 8 + 5 = 30 which is divisible by 3 --- Meet equation 1

[3 + (b - a)] = [3 + (5 - 8)] = 0 ---Meet equation 2

Since these values satisfies both equation 1 and equation 2, this is the answer

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36 33917
Q:

If the product 4864*9 P 2 is divisible by 12, the value of p:

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: A) 1

Explanation:

Clearly 4864 is divisible by 4
So, 9 P 2 must be divisible by 3. So (9+P+2) must be divisible by 3.
So P=1.

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74 41821
Q:

854*854*854-276*276*276854*854+854*276+276*276=?

A) 546 B) 578
C) 607 D) None of these
 
Answer & Explanation Answer: B) 578

Explanation:

Given exp . is like this 854*854*854-276*276*276854*854+854*276+276*276=?

 

so ans = 854 - 276 = 578

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3 6411
Q:

934+7217-9115=?

A) 7 + 719/1020 B) 9 + 817/1020
C) 9 + 719/1020 D) 7 + 817/1020
 
Answer & Explanation Answer: D) 7 + 817/1020

Explanation:

given sum =9+34+7+217-9+115

 

9+7+9+34+217-115

 

=> 7+765+120-681020=>7+8171020 

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3 5922