9
Q:

# In an examination, 34% of the students failed in Mathematics and 42% faiied in English. If 20% of the students failed in both the subjects, then the percentage of students who passed in both the subjects was :

 A) 34 % B) 44 % C) 54 % D) 64 %

Explanation:

n (A) = 34, n (B) = 42, n (A   B) = 20.

So, n (A  U B) = n (A) + n(B) - n(A B) = 34 + 42 - 20 = 56.

Percentage failed in either or both the subjects = 56.

Hence, percentage passed = (100 - 66)% = 44%.

Q:

What is 6% of 3,50,000?

 A) 19500 B) 21000 C) 23600 D) 24000

Explanation:

6% of 350000

Hence, 6% of 3,50,000 = 21,000.

1 106
Q:

20% of 120?

 A) 20 B) 24 C) 32 D) 36

Explanation:

20% of 120

20 x 120/100

= 4 x 6

= 24

Hence, 20% of 120 = 24.

1 159
Q:

Twenty percent of Karthik’s monthly salary is equal to thirty two percent of Nikitha’s monthly salary. Vipin’s monthly salary is four fifth that of Nikitha’s monthly salary. If Vipin’s annual salary is Rs. 3.84 lakhs, what is Karthik’s monthly salary?

 A) 32,000 B) 64,000 C) 40,000 D) 52,000

Explanation:

From the given data,

20% of K = 32% of N

V = 4/5 N

Given Vipin's salary = 3.84 lpa = 3.84/12 = 32,000 per month

Now, N = 5/4 x 32000 = 40000

Now K = 32/20 x 40000 = 64000

Hence, karthik's monthly salary = Rs. 64000.

2 225
Q:

1/4 of 12?

 A) 4 B) 3 C) 2 D) 1

Explanation:

1/4 of 12

= 1/4 x 12

= 3

Hence, 1/4 of 12 = 3.

0 184
Q:

40% of 75 + 80% of 25 = K% of 250

Find the value of K?

 A) 10 B) 20 C) 30 D) 35

Explanation:

From the given data,

0 379
Q:

In a class of 80 students and 5 teachers, each student got sweets that are 15% of the total number of students and each teacher got sweets that are 25% of the total number of students. How many sweets were there?

 A) 1060 B) 960 C) 860 D) 760

Explanation:

From the given data,

80 x 15/100 of 80 + 5 x 80 x 25/100

= 960 + 100

= 1060.

5 395
Q:

Sairam spent Rs. 38460 on the renovation of his home and Rs. 24468 on buying TV set and remained with 28% of the total amount. What was the total amount?

 A) Rs. 87400 B) Rs. 68700 C) Rs. 74000 D) Rs. 94060

Explanation:

Let the total amount he had with = Rs. p

From the given data,

p - 38460 - 24468 = 28p/100

p - 28p/100 = 24468 + 38460

72p/100 = 62928

72p = 62928 x 100

p = 62928 x 100/72

p = 87400

Hence, the total amount he had = p = Rs. 87400.

4 384
Q:

A jar can 20 litre milk. From the jar, 4 litres milk was taken out and replaced with an equal quantity of water. If 4 litres of the newly formed mixture is taken out of the can, then what is the final quantity of milk left in the can?

 A) 14.5 lit B) 12.8 lit C) 11.6 lit D) 10.46 lit