A) 36 | B) 25 |

C) 42 | D) 120 |

Explanation:

There are 6 letters in the given word, out of which there are 3 vowels and 3 consonants.

Let us mark these positions as under:

(1) (2) (3) (4) (5) (6)

Now, 3 vowels can be placed at any of the three places out 4, marked 1, 3, 5.

Number of ways of arranging the vowels = $3{P}_{3}$ = 3! = 6.

Also, the 3 consonants can be arranged at the remaining 3 positions.

Number of ways of these arrangements = $3{P}_{3}$ = 3! = 6.

Total number of ways = (6 x 6) = 36.

A) 25 : 28 | B) 36 : 7 |

C) 8 :25 | D) 12 : 7 |

A) M | B) J |

C) B | D) O |

Explanation:

Thus after arranging the letters as per English alphabetical series; we get; Thus 4th letter from the left end will be K.

A) 2 | B) 3 |

C) 4 | D) 5 |

A) T | B) X |

C) N | D) R |

Explanation:

The first, the seventh, the ninth and the tenth letters of the word RECREATIONAL are R, T, O and N respectively. Meaningful word from these letters is only TORN. The third letter of the word is ‘R’.

A) 16! × 2 | B) 14! × 2 |

C) 18! × 2 | D) 14! |

A) 1/5225 | B) 1/5525 |

C) 5525 | D) 1/525 |

Explanation:

n(S) = 52C3 = 132600/6 = 22100

n(E) = 4C3 = 24/6 = 4