A) 49 | B) 7! |

C) 7^7 | D) 7^3 |

Explanation:

There are seven positions to be filled.

The first position can be filled using any of the 7 letters contained in PROBLEM.

The second position can be filled by the remaining 6 letters as the letters should not repeat.

The third position can be filled by the remaining 5 letters only and so on.

Therefore, the total number of ways of rearranging the 7 letter word = 7*6*5*4*3*2*1 = 7! ways.

A) 25 : 28 | B) 36 : 7 |

C) 8 :25 | D) 12 : 7 |

A) M | B) J |

C) B | D) O |

Explanation:

Thus after arranging the letters as per English alphabetical series; we get; Thus 4th letter from the left end will be K.

A) 2 | B) 3 |

C) 4 | D) 5 |

A) T | B) X |

C) N | D) R |

Explanation:

The first, the seventh, the ninth and the tenth letters of the word RECREATIONAL are R, T, O and N respectively. Meaningful word from these letters is only TORN. The third letter of the word is ‘R’.

A) 16! × 2 | B) 14! × 2 |

C) 18! × 2 | D) 14! |

A) 1/5225 | B) 1/5525 |

C) 5525 | D) 1/525 |

Explanation:

n(S) = 52C3 = 132600/6 = 22100

n(E) = 4C3 = 24/6 = 4