Sawaal
109
Q:

A basket contains 10 apples and 20 oranges out of which 3 apples and 5 oranges are defective. If we choose two fruits at random, what is the probability that either both are oranges or both are non defective?

A) 136/345 B) 17/87
C) 316/435 D) 158/435

Answer:   C) 316/435



Explanation:

ns=C230

 

 Let A be the event of getting two oranges and 

 

 B be the event of getting two non-defective fruits.

 

 and A∩B be the event of getting two non-defective oranges

 

 ∴ PA=C220C230, PB=C222C230 and PA∩B=C215C230

 

 ∴PA∪B=PA+PB-PA∩B

 

= C220C230+C222C230-C215C230=316435

Subject: Probability
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