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55
Q:

A word consists of 9 letters; 5 consonants and 4 vowels.Three letters are choosen at random. What is the probability that more than one vowel will be selected ?

A) 13/42 B) 17/42
C) 5/42 D) 3/14

Answer:   B) 17/42



Explanation:

3 letters can be choosen out of 9 letters in 9C3 ways.

 

More than one vowels ( 2 vowels + 1 consonant  or  3 vowels ) can be choosen in (4C2*5C1)+4C3 ways

 

Hence,required probability = 4C2*5C1+4C39C3 = 17/42

Subject: Probability
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